Since 
are in geometric progression, if 
is the common ratio between consecutive terms, then
Since are also in arithmetic progression, if 
is the common difference between consecutive terms, then
Given that 
, we have
It follows that
Solve for .
so the only possible sequence is {3, 3, 3, …}.
Answer:
1/40
Step-by-step explanation:
Probability: (number of ways to achieve the desired result / number of possible results)
For example, if we want a coin to land on heads:
We know there is one way for it to land on heads and two possible outcomes. Thus, the possibility of flipping a head is 1/2.
Using this, we know that there are 5 grey marbles (the desired result) and there are (5 + 3 + 6 + 2 + 4) total possible outcomes. The probability of drawing a grey marble is then:
5 / (5 + 3 + 6 + 2 + 4) =
5/20 =
1/4
We also know that there are 2 yellow marbles, so the probability of drawing one would be: 2 / 20 = 1/10
To find the probability of both of these events happening right after each other, multiply the probability of them each happening together.
1/4 * 1/10 = 1/40 chance of picking a grey marble and then a yellow marble.
-7 + -3 = -10 So.... it can be any negative integers that would equal -10.
EX: -6 + -4 = -10 or -5 + -5 = -10
0.080
can be that because you add an extra zero so the number is smaller
Their distance differs by 15 miles for each hour of travel time. Thus, the travel time of interest is
.. (180 -144) miles/(15 miles/hour) = 2.4 hour
The red car's speed is 180 mi/(2.4 h) = 75 mi/h.
The blue car's speed is 144 mi/(2.4 h) = 60 mi/h.
