3. Simplify 3 +2× 4+6/2-5 -1 4 2 25 3

What is the formula for surface area

zubka84 [21]

The area is perimeter times height plus area of the bases

6 0

3 years ago

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Find the coordinates of point P that partitions segment MN in the ratio 3:2 if M(-3,-3) and N(4,2).

SpyIntel [72]

Answer:

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Step-by-step explanation:

3 0

3 years ago

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What is the volume of the composite figure below? (formula for volume of a prism is 1/3 Bh where B is the area of the base.)

arsen [322]

Answer:

Last Option; 84 cu. mm

Step-by-step explanation:

We know that;

Volume = 1/3(Bh)

And that this is figure has a square base, therefore B that represents the area of the base will be: 6 * 6 = 36

And height = 7mm

Therefore we can say;

Volume = (1/3)*(6 x 6)*(7)

Volume = (1/3)*(36)*(7)

Volume = (12)*(7)

Volume = 84

Hope this helps!

6 0

3 years ago

Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

5 0

3 years ago

. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i

KIM [24]

Answer:

Error of Andrew: Made incorrect factors from the roots

Step-by-step explanation:

Roots of the polynomial are: 3, 2 + 2i, 2 - 2i. According to the factor theorem, if a is a root of the polynomial P(x), then (x - a) is a factor of P(x). According to this definition:

(x - 3) , (x - (2 + 2i)) , (x - (2 - 2i)) are factors of the required polynomial.

Simplifying the brackets, we get:

(x - 3), (x - 2 - 2i), (x - 2 + 2i) are factors of the required polynomial.

This is the step where Andrew made the error. The factors will always be of the form (x - a) , not (x + a). Andrew wrote the complex factors in form of (x + a) which resulted in the wrong answer.

So, the polynomial would be:

$(x - 3)(x - 2 - 2i)(x - 2+2i)=0\\\\ (x-3)(x^{2}-2x+2xi-2x+4-4i-2xi+4i-4i^{2})=0\\\\ (x-3)(x^{2}-4x+4+4)=0\\\\ (x-3)(x^{2}-4x+8)=0\\\\ x^{3}-4x^{2}+8x-3x^{2}+12x-24=0\\\\ x^{3}-7x^{2}+20x-24=0$

7 0

3 years ago

3. Simplify 3 +2× 4+6/2-5 -142253​

3. Simplify 3 +2× 4+6/2-5 -142253