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victus00 [196]
2 years ago
6

Select the correct statement or statements about compounds and molecules:

Mathematics
2 answers:
sineoko [7]2 years ago
7 0

Answer:

1) and 3)

Step-by-step explanation:

Ksenya-84 [330]2 years ago
6 0

Answer:

<h3> 1) Compounds don’t act like their elements; Compounds act like a different substance.</h3><h3>3) A molecule is two or more atoms bonded together.</h3>

Step-by-step explanation:

A compound is a molecule which is made of atoms from different elements.

Compounds are useful beacuse they don't actually act like their elements. For example, if you think about H_{2}O, you observe that it's a compund of 2 atoms of hydrogen and 1 atom of oxygen, but the compund doesn't act like hydrogen or oxygen, it's water. Therefore, the first choice is correct.

Now, as we said before, a molecule is form by atoms, specifically by two or more, because a single atom cannot form a molecule, it would be just an atom by itself. Therefore, the third choice is correct.

So, the right choices are 1 and 3.

You might be interested in
A grocery store is offering a sale on bread and soup. Khalil buys four cans of soup and
Flura [38]

Answer:

a) cblo

2)$3.44

Step-by-step explanation:

4 cans and 3 loaves=11.67

8 cans and 1 loaf= 12.89.

Set up equation:

x=cans

y=loaves

4x+3y=11.67\\8x+y=12.89 This is the answer for question A.

Multiply eq1 by 2:

8x+6y=23.34

Subtract eq3 by eq2:

5y=10.45\\y=2.09

Substitute:

8x+2.09=12.89\\8x=10.8\\x=1.35

One can of soup and one loaf of bread=

1.35+2.09 or 3.44

So:

$3.44

Hope this helps :D Please hit the crown if u can !!

6 0
3 years ago
Solve for x(need help)
bija089 [108]

Answer:

x = 18

Step-by-step explanation:

I the given triangle, it appears that M and N are the midpoints of the segments BG and BD respectively. If it so, then let us solve it.

By mid segment theorem:

2MN = GD

2(6x - 51) = 114

12x - 102 = 114

12x = 114 + 102

12x = 216

x = 216/12

x = 18

4 0
3 years ago
*Easy* &amp; will mark brainest!! Does the image above mean no solution or infinite solutions? please let me know!
jenyasd209 [6]

Answer:

No solution.

Step-by-step explanation:

That image is of the symbol of the empty set. The solution set is empty, which means there is no solution.

8 0
2 years ago
Read 2 more answers
1 point
stepan [7]

Answer:

y = 250x

Step-by-step explanation:

<em>The options are not given; however, the question can still be answered.</em>

Given

Direct Proportion:

In 20 minutes, y = 250 bottles

Required

Determine the graph

<em>In the first 20 minutes, y = 250</em>

<em>In the next 20 minutes, y = 250 + 250 = 500</em>

<em>In the next 20 minutes, y = 500 + 250 = 750</em>

<em />

This gives a arithmetic sequence:

250, 500, 750, ........

Next, is to determine the equation of the sequence using;

T_n = a + (n - 1)d

In this case;

T_n = y

x = n

a = 250

d = 750 - 500 = 500 - 250 = 250

Substitute these values in the above formula;

y = 250 + (x - 1) * 250

Open Bracket

y = 250 + 250x - 250

Collect Like Terms

y = 250x + 250 - 250

y = 250x

Hence; the graph that shows the given description is the graph with equation y = 250x

4 0
2 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
2 years ago
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