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victus00 [196]
2 years ago
6

Select the correct statement or statements about compounds and molecules:

Mathematics
2 answers:
sineoko [7]2 years ago
7 0

Answer:

1) and 3)

Step-by-step explanation:

Ksenya-84 [330]2 years ago
6 0

Answer:

<h3> 1) Compounds don’t act like their elements; Compounds act like a different substance.</h3><h3>3) A molecule is two or more atoms bonded together.</h3>

Step-by-step explanation:

A compound is a molecule which is made of atoms from different elements.

Compounds are useful beacuse they don't actually act like their elements. For example, if you think about H_{2}O, you observe that it's a compund of 2 atoms of hydrogen and 1 atom of oxygen, but the compund doesn't act like hydrogen or oxygen, it's water. Therefore, the first choice is correct.

Now, as we said before, a molecule is form by atoms, specifically by two or more, because a single atom cannot form a molecule, it would be just an atom by itself. Therefore, the third choice is correct.

So, the right choices are 1 and 3.

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Aiden has some $1 bills and $5 bills. He has 6 bills worth $22 total in his wallet. How many $1 bills does he have?
xxMikexx [17]
Four $5 bills and two $1 bills
In total it’s six bills
5(4)=20 and 1(2)=2
20+2=22
5 0
3 years ago
If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
Vlad [161]

Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

7 0
3 years ago
Find the area of the following circle. (Round answer to the nearest whole number.) Circumference = 280 cm. (Hint: Find r from C
Marrrta [24]
Find r :
C=2πr
280=2(3.14)r
r=280/2(3.14)
r=44.6cm

find area :
A=πr²
A=3.14(44.6)²
A=6246 cm²

Answer : 4)6,246
4 0
3 years ago
Read 2 more answers
2. Select the factor table with the appropriate
Alexandra [31]

Answer:

60

Step-by-step explanation:

5+5+5+5+5+5+5+5+5+5+5+5

4 0
3 years ago
If an integer m is divisible by both 10 and 12, then it must also be divisible by which of the following?
Murrr4er [49]

Answer:

20

Step-by-step explanation:

an integer m is divisible by both 10 and 12

Lets write the prime factor for each number

the prime factor for 10 is 5,2

the prime factor for 12 is 3,2,2

Now take the product of the  prime factors that are not in common and also in common5 \cdot 3 \cdot 2 \fdot 2= 60

60 is divisible  by 20

so answer is 20

3 0
3 years ago
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