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3 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

ratelena [41]3 years ago

4 0

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

$m$ - slope

$b$ - y-intercept

$11)\ m=-1,\ b=2\\\\y=-x+2\\\\12)\ m=-\dfrac{3}{2},\ b=3\\\\y=-\dfrac{3}{2}x+3\\\\13)\ m=3,\ y=-2\\\\y=3x-2\\\\14)\ y=\dfrac{3}{4},\ b=1\\\\y=\dfrac{3}{4}x+1\\\\15)\ m=\dfrac{1}{2},\ b=1\\\\y=\dfrac{1}{2}x+1\\\\16)\ m=-\dfrac{2}{5},\ b=0\\\\y=-\dfrac{2}{5}x\\\\17)\ m=-7,\ b=2\\\\y=-7x+2\\\\18)\ m=\dfrac{4}{3},\ b=-4\\\\y=\dfrac{4}{3}x-4$

19) and 20) you have in other your question.

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Simplify cos omega tan omega

Nana76 [90]

Answer:

B) sin Ф

Step-by-step explanation:

Use the pythagorean identity for cos and tan

tan = $\frac{sin}{cos }$ Multiply both sides by cos

sin Ф = sin Ф

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3 years ago

If there os 150 capacity and 36 os used what os the remaining percentage

Veseljchak [2.6K]

150 - 36 = 114 os remaining;
114/150 = 0,76 (as a decimal) = 76% (as a percentage);

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3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago

Help need it asap plessss

Dennis_Churaev [7]

Answer:

C) $14.2

Step-by-step explanation:

$3 is flat value. minimum price. $0.8 per mile for 14 miles is 0.8x14 which equals to 11.2. Add $3 and get $14.2.

7 0

3 years ago

Read 2 more answers

Find the measure of \angle G∠G. Round your answer to the nearest tenth (one decimal place).

Law Incorporation [45]

Hi there!

$\large\boxed{G \approx 55.44^{o}}$

To solve, we can use right triangle trigonometry.

Recall that:

sin = O/H, cos = A/H, tan = O/A.

For angle G, HF is its OPPOSITE side, and FG is the hypotenuse.

Therefore, we must use sine to evaluate:

sinG = 14 / 17

sin⁻¹ (14/17) = ∠G. Evaluate using a calculator.

∠G ≈ 55.44°

6 0

3 years ago