Answer:
£50 and £300
Step-by-step explanation:
Sum the parts of the ratio 1 + 6 = 7 parts
Divide the amount by 7 to find the value of one part of the ratio
£350 ÷ 7 = £50 ← value of 1 part of ratio
Hence
1 person receives £50
the other person receives 6 × £50 = £300
Answer:
The larger number is -6, the smaller number is -15
Step-by-step explanation:
We have two numbers, a and b.
We know that one number is larger than another by 9.
Then we can write:
a = b + 9
then a is larger than b by 9 units.
If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:
(a + 10) + 3*b = -41
So we got two equations:
a = b + 9
(a + 10) + 3*b = -41
This is a system of equations.
One way to solve this is first isolate one variable in one of the two equations:
But we can see that the variable "a" is already isolated in the first equation, so we have:
a = b + 9
now we can replace that in the other equation:
(a + 10) + 3*b = -41
(b + 9) + 10 + 3*b = -41
now we can solve this for b.
9 + b + 10 + 3b = -41
(9 + 10) + (3b + b) = -41
19 + 4b = -41
4b = -41 -19 = -60
b = -60/4 = -15
b = -15
then:
a = b + 9
a = -15 + 9 = -6
a = -6
Y= 360.5(1+0.03)^1
y= 360.5(1.03)^1
y= 360.5(1.03)
y= 371.315
y= 371.32
first you do 8×12=92 then you do 92+2=94 94×12=1,128 so you save1,128 if I'm not wrong
Let the amount invested at 4% be = x
Let the amount invested at 3% be = y
Given is:
or 
.... (1)
As, total income for the two investments is $194, so equation is:
....(2)
Putting value of x from (1) in (2)
And x=5200-y
Hence, money invested at 4% is $3800 and money invested at 3% is $1400
