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2 years ago

Can someone please give me the (Answers) to this? ... please ...

Mathematics

2 answers:

Korvikt [17]2 years ago

3 0

Answer:

6:A

7;B

8;c

9;A

10:c

11;b

12:A

yarga [219]2 years ago

3 0

Answer:

6. Commander David Scott

7. They dropped at the same speed

8. Scale (I think)

9. B

10. True

11. Gravity (not sure)

12. C

17. Weaker

18. Ellipsoid (also not sure)

19. Towards the Earth’s center

20. I don’t know this

21. Center

22. B

Step-by-step explanation:

Not sure about some of them (like 19 because it feels like it can have more than one answer) but yeah the others are self-explanatory

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What is 82 divided by 4 in whole numbers

mr_godi [17]

It would 20.5, but rounded off would be 21

8 0

3 years ago

PLSSS HELLLPP MY QUARTER ENDS TMMR!!! can someone solve y=___x+___

natulia [17]

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2 years ago

The sum of a number and five divided by fifteen

natta225 [31]

Answer:

Option F

Step-by-step explanation:

Let the number be n.

Sum of a number and 5 is n + 5.

Sum of a number and five divided by fifteen is

( n + 5 ) / 15

5 0

3 years ago

Oh and alsoo can someone plzzzzz add an explanation

Pani-rosa [81]

Answer:

Brian sold 35 tickets

Step-by-step explanation:

42/6 = 7

7 x 5 = 35

35/42 = 5/6

Brian sold 35 tickets

(I know this isn't part of the question, but Brain didn't sell 7 tickets)

5 0

3 years ago

The location of point V is (-3,3). The location of point X is (9,13). Determine the location of point W which is 3/4 of the way

Inga [223]

ANSWER

$W(\frac{9}{7},\frac{51}{7} )$

EXPLANATION

We want to find the coordinates of the point W(x,y) which divides V(-3,3) and X(9,13) in the ratio m:n=3:4.

The x-coordinate of this point is given by:

$x= \frac{mx_2+nx_1}{m + n}$

$x= \frac{3(9)+4( - 3)}{4 + 3}$

$x= \frac{21 - 12}{4 + 3}$

$x= \frac{9}{7}$

The y-coordinates is given by;

$y= \frac{my_2+ny_1}{m + n}$

$y= \frac{3(13)+4( 3)}{4 + 3}$

$y= \frac{39+12}{4 + 3}$

$y= \frac{51}{7}$

Hence

$W(\frac{9}{7},\frac{51}{7} )$

3 0

3 years ago

￼Can someone please give me the (Answers) to this? ... please ...

Can someone please give me the (Answers) to this? ... please ...