Let distance be s and velocity be v
s = 5t⁴ - 10t² + 6
We know velocity is the change in distance per unit time, so
v = ds/dt
v = 20t³ - 20t
(5q2 − r2s)(25q^4+5q^2r^2s+1r^4s^2)
Maybe around 10 this is a tricky question.
Different dealerships sell different amounts
So you would start with removing the parentheses so 6- - 4 would be 6+4 because the double negative and then that would be 10 so 7 times 10 so your answer is 70
There u go I hope this helps
