Ask question

Ask question

All categories

2 years ago

15

A company prints designs on T-shirts. They charge $40 for set-up costs plus $12 hirt. Complete the table of values for this situ

ation.

2 answers:

ehidna [41]2 years ago

7 0

Answer:1- $52 {40+12(1)=}

5- $100 {40+12(5)=}

10 - $160 {40+12(10)=}

50 - $640 {40+12(50)=}

LuckyWell [14K]2 years ago

3 0

Answer:

thanks

Step-by-step explanation:

You might be interested in

Round 1596 to the nearest thousand.

Thepotemich [5.8K]

1500 that is the answer for ur question

3 0

2 years ago

Read 2 more answers

Triangles P and Q are similar.

svp [43]

Answer:

if i labeled the triangle correctly BC= sqrt 97, ZX=32sqrt 2

Step-by-step explanation:

join my stream and tell me how to label the triangle

(ChildOfHermes)

6 0

2 years ago

What is 6 divided by 1/3

-BARSIC- [3]

6 / 1/3 = 18

Hope I helped!

~ Zoe

7 0

3 years ago

Read 2 more answers

What is 8 - 5 3/16 I gotta know

ValentinkaMS [17]

Answer:

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

Answer:

45/16

3 0

3 years ago

For each of the following vector fields

olga nikolaevna [1]

(A)

$\dfrac{\partial f}{\partial x}=-16x+2y$

$\implies f(x,y)=-8x^2+2xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y$

$\implies g(y)=5y^2+C$

$\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}$

(B)

$\dfrac{\partial f}{\partial x}=-8y$

$\implies f(x,y)=-8xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x$

$\implies \dfrac{\mathrm dg}{\mathrm dy}=x$

But we assume $g(y)$ is a function of $y$ alone, so there is not potential function here.

(C)

$\dfrac{\partial f}{\partial x}=-8\sin y$

$\implies f(x,y)=-8x\sin y+g(x,y)$

$\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=4y$

$\implies g(y)=2y^2+C$

$\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}$

For (A) and (C), we have $f(0,0)=0$ , which makes $C=0$ for both.

4 0

3 years ago