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3 years ago

Express 10 2/3 in simplest radical form

1 answer:

8 0

<h2>Hey there! </h2><h2> $\bold{Formula: \dfrac{a \times c + b}{c}}$ </h2><h2> $\bold{10\dfrac{2}{3}=}\bold{\dfrac{10\times3+2}{3}}$ </h2><h2> $\bold{Solving\ for\ your\ numerator\downarrow}}\\\\\bold{10\times3+2=?}\\ \bold{10\times3=30}\\ \bold{30+2=32}$ </h2><h2> $\bold{b=32\leftarrow numerator}\\\\\\\\ \bold{c =3\leftarrow denominator}$ </h2><h2> $\boxed{\boxed{\bold{Answer: \dfrac{32}{3}}}}\huge\checkmark$ </h2><h2>Good luck on your assignment and enjoy your day!</h2><h2>~ $\frak{LoveYourselfFirst:)}$ </h2><h2 /><h2 />

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The height of a certain banner is equal to one third of its length. If the banner is 5 ft tall, write the equation that can be u

pav-90 [236]

Answer:

$L=3h$

Step-by-step explanation:

Let height of a banner be $h$ , then we know that this is $\frac{1}{3}$ of the length $L$ of the banner; so we have

$h=\frac{1}{3} L$ .

Now we can rearrange this equation to solve for the length of the banner given it's height:

$L=3h$

So there we have it!

If the banner is 5 ft tall, then it's length will be:

$L=3*5=15ft$

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2 years ago

Give the ordered pair of the 3rd Critical point.<br> Y = 4cos10(x - 12°) +16

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2 years ago

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Vikentia [17]

Answer:

Step-by-step explanation:

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2 years ago

How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At

ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

$=s=3 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

That is Speed of light in another medium

$=w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

$\rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}$

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3 years ago

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Ksju [112]

How do you solve this

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3 years ago

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