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s344n2d4d5 [400]
2 years ago
11

This unintelligent brain of mine decided to charge my phone overnight thinking that nothing bad will happen ;-; the next morning

i woke up to find it not turning on i can go to a phone technician so is there anything i can do myself please i need help before January 10
Computers and Technology
1 answer:
spin [16.1K]2 years ago
7 0

There are different reasons that may be the cause of the phone not turning on. The best things to do is to check the power cord first to known where the fault is coming from.

Then one can try using a different chord for your phone, or try your power cord with another phone. This will help you to recognize the fault.

When you notice that your cord did  works in another device, you can then know that your battery need replacing. But If a different cord do works in your phone, then use that cord to charges it and you just need to replace your original cord.

Learn more about Phone from

brainly.com/question/12218769

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Write a loop that reads c-strings from standard input where the c-string is either "land", "air", or "water". The loop terminate
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Answer:

I am writing a C++ code.        

#include <iostream> // for input output functions

using namespace std; // identifies objects like cin cout

int main() { //start of main() function body

string c_string; // stores the string entered by user from land water or air

int land=0; // contains the number of times land string is read in

int air=0; //contains the number of times air string is read in

int water = 0; //contains the number of times water string is read in

cin>>c_string; //reads the string entered by user from air water or land

/*while loop continues to execute until user enters xxxxx or maximum length of a string exceeds 8 */

while(c_string!= "xxxxx" && c_string.length()<=8) {

if(c_string=="land"){ // if string entered by user is land

land = land + 1;} //counts and increments each occurrence of land string by 1

else if(c_string=="air"){// if string entered by user is air

air = air + 1;}// counts and increments each occurrence of string air by 1

else if(c_string=="water"){// if string entered by user is water

water = water + 1;}//counts and increments each occurrence of air by 1

cin>>c_string;}

/* keeps reading the string entered by user from land air or water, until the loop breaks after the user enters xxxxx or user enters a string whose length is greater than 8 */

//prints the number of times land, air and water are read in

cout << "land:"<<land;

cout << endl<<"air:"<<air;

cout << endl<< "water:"<<water; }                      

                                                                                     

Explanation:

Everything is well explained in the comments above.

The program prompts the user to input strings. These strings are either land air or water. The while loop continues to read the input strings until user enters xxxxx or the string entered by user exceeds the length 8. Both these terminating conditions are added in the while loop. After the loop terminates, the number of times land, air and water strings are read is displayed on the output screen. Any other string entered by user other than these 3 is ignored. The program along with the output is attached.

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Answer:

The correct answer is:

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Explanation:

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{

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Hence, the correct answer is:

C. ndx = 0;

while (ndx < 3) {

ar[ndx] = 0;

ndx++;

}

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