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3 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics

2 answers:

DerKrebs [107]3 years ago

7 0

Answer:

A. 1 1/2

Step-by-step explanation:

lianna [129]3 years ago

4 0

Answer:

A, 1 1/2 of an inch.

Step-by-step explanation:

The length is 1.3 of an inch.

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How to find the θ in this equation: tan(θ+16°)=1/tan(θ+60°) by using the trigonometric identities?thanks

DedPeter [7]

Answer:

$\huge \theta =7°$

Step-by-step explanation:

$tan( \theta + 16 \degree) = \frac{1}{tan( \theta + 60 \degree) } \\ tan( \theta + 16 \degree) =cot( \theta + 60 \degree) \\ tan( \theta + 16 \degree) = tan \{90 \degree - (\theta + 60\degree) \} \\ \theta + 16 \degree = 90 \degree - \theta - 60\degree \\ \theta +\theta = 30 \degree - 16\degree \\2 \theta = 14 \degree \\ \theta = \frac{14 \degree}{2} \\ \huge \red{ \boxed{\theta =7 \degree}}$

7 0

3 years ago

Please help:(((

Nana76 [90]

Answer: $(x+3)^2=-4(y-3)$

Step-by-step explanation:

From the figure, it is downward parabola of the form $x^2=-4ay$

The parabola has its vertex at $(-3,3)$

Distance between parabola vertex and its directrix is 1 unit.

So, the value of a is 1

Hence, the equation of parabola is $(x+3)^2=-4(y-3)$

7 0

3 years ago

Find the length of the arc, s, on a circle of radius r intercepted by a central angle 0. Express the arc length in terms of π.

777dan777 [17]

Answer:

5π or 15.71 inches

Step-by-step explanation:

Length of an arc = $\frac{x}{360}$ × 2πr

Where x is the angle and r is the radius

so $\frac{90\\}{360}$ × 2 × π × 10

0.25 × 2 × π × 10

Arc length = 5π inches (answer in terms of π)

= 15.71 inches (answer in two decimal places)

8 0

3 years ago

the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant

Tamiku [17]

Answer:

The rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters is $24\pi \:\frac{cm^3}{s}$

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

$\frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}$
$\frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}$
The volume of a cone of radius r and height h is given by $V=\frac{1}{3} \pi r^2 h$

We want to find the rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

$\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]$

Substituting the values we know into the above formula:

$\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}$

5 0

4 years ago

Factor -2 out of negative 6x +10

Kryger [21]

The answer to the question

7 0

3 years ago