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MrRa [10]
3 years ago
7

I need help on all besides a

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

B) (-mn)^3  (-1)^3m^3n^3       -m^3n^3

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If Ill m, solve for x.<br> (8x - 71)<br> (5x + 7)<br> x =
horsena [70]

Answer:

x=26

Step-by-step explanation:

by definition of alternate exterior angle rule 8x -71 = 5x +7

What you want to do is get your X's on one side I recommend subtracting 5x so that you don't have to deal with negative values.

8x-5x-71=5x-5x+7

3x-71=7

add 71 to both sides the goal now is trying to get by itself

3x-71+71=7+71

3x=78

now divide both sides by 3

3x/3=78/3

x=26

8 0
3 years ago
Read 2 more answers
Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
2 years ago
Read 2 more answers
Practice: Subtract Three-Digit Num<br> 480 - 371<br> =
BigorU [14]
It is 109
Hope it helps !!
4 0
3 years ago
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ABCD is a Rhombus with side length 10 cm. Angle ADC = 40. DAC is a sector of a circle with center D. BAC is a sector of a circle
Natasha_Volkova [10]

The value of the <em>shaded</em> area is approximately 34.907 square centimeters.

<h3>How to calculate the area between a rhombus and a circle</h3>

According to the description in statement we prepared a representation of the figure in the image attached below. The <em>shaded</em> area is equal to the area of the <em>circle</em> sector (A), in square centimeters:

A = \frac{\theta\cdot \pi \cdot R^{2}}{360} (1)

Where:

  • R - Length of the radius, in centimeters.
  • \theta - Angle of circle arc, in degrees.

If we know that \theta = 40^{\circ} and R = 10\,cm, then the area of the circle is:

A = \frac{(40)\cdot \pi\cdot (10\,cm)^{2}}{360}

A\approx 34.907\,cm^{2}

The value of the <em>shaded</em> area is approximately 34.907 square centimeters. \blacksquare

To learn more on areas, we kindly invite to check this verified question: brainly.com/question/16151549

7 0
2 years ago
Please help and show work!!
Jlenok [28]

A(1, 1), B(7, 1), C(1, 9)

AB = 7 - 1 = 6

AC = 9 - 1 = 8

Use the Pythagorean theorem:

AB² + AC² = BC²

Substitute:

BC² = 6² + 8²

BC² = 36 + 64

BC² = 100 → BC = √100 → BC = 10

The perimeter of ΔABC:

P = 6 + 8 + 10 = 24

<h3>Answer: 24 units</h3>
5 0
3 years ago
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