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MrRa [10]
3 years ago
7

I need help on all besides a

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

B) (-mn)^3  (-1)^3m^3n^3       -m^3n^3

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Find dy/dx by implicit differentiation for ycos(x)=xcos(y)
alekssr [168]

Answer:

dy/dx = (cos y + y sin x) / (cos x + x sin y)

Step-by-step explanation:

y cos x = x cos y

y (-sin x) + dy/dx cos x = x (-sin y dy/dx) + cos y

-y sin x + dy/dx cos x = -x sin y dy/dx + cos y

dy/dx (cos x + x sin y) = cos y + y sin x

dy/dx = (cos y + y sin x) / (cos x + x sin y)

5 0
3 years ago
Any help if possible Thank you ❤
Mariana [72]
v =  \frac{1}{3} \pi {r}^{2} h \\ r = 8 \: cm \\ h = 15 \: cm
From the diagram, we can see that the radius of the cone is 8cm and the height of the cone is 15cm. We then just plug these numbers into the formula and simplify:
v =  \frac{1}{3} \pi {r}^{2} h \\ v =  \frac{1}{3} \pi {(8)}^{2} (15) \\ v = 320\pi
The volume of the cone is approximately 1005.3096 cm^3. With 3 sig figs, this is 1010 cm^3.
3 0
3 years ago
FedEx will ship the Olympic medals from the producer to Japan. Each medal weighs 0.5 kilograms. A box carries 6 medals. If FedEx
kherson [118]

Answer:

42

Step-by-step explanation:

weight of medals:

30 (0,5) = 15 kg

cost of 5 kg:

28/2 = 14

cost of shipping:

14+28=42

6 0
3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​, and a standard deviation given by
kirza4 [7]

Answer: a) The probability is approximately = 0.5793

b) The probability is approximately=0.8810

Step-by-step explanation:

Given : Mean : \mu= 62.5\text{ in}

Standard deviation : \sigma = \text{2.5 in}

a) The formula for z -score :

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Sample size = 1

For x= 63 in. ,

z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{1}}}=0.2

The p-value = P(z

0.5792597\approx0.5793

Thus, the probability is approximately = 0.5793

b)  Sample size = 35

For x= 63 ,

z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{35}}}\approx1.18

The p-value = P(z

= 0.8809999\approx0.8810

Thus , the probability is approximately=0.8810.

6 0
3 years ago
What is the longest line segment that can be drawn in a right rectangular prism that is 15 cm​ long, 11 cm​ wide, and 10 cm​ tal
sammy [17]

Answer:

  √446 ≈ 21.12 cm

Step-by-step explanation:

The longest dimension of a rectangular prism is the length of the space diagonal from one corner to the opposite corner through the center of the prism. The Pythagorean theorm tells you the square of its length is the sum of the squares of the dimensions of the prism:

  d² = (15 cm)² +(11 cm)² +(10 cm)² = (225 +121 +100) cm² = 446 cm²

  d = √446 cm ≈ 21.12 cm

The longest line segment that can be drawn in a right rectangular prism is about 21.12 cm.

_____

<em>Additional comment</em>

The square of the face diagonal is the sum of the squares of the dimensions of that face. The square of the space diagonal will be the sum of that square and the square of the remaining prism dimenaion, hence the sum of squares of all three prism dimensions.

8 0
2 years ago
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