Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
2x+2≥20
2x≥18
x≥9
closed circle on 9 because of the = in ≥ and the line going off to the right
please ask if you need more information or clarification
M = 1 - 2 / 3 - 1
m = - 1 / 2
The answer & explanation for this question is given in the attachment below.
Answer:
4+3 squared 3 equals 9.19 and 4-3 squared 3 equals -1.19
Step-by-step explanation:
