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Nitella [24]
3 years ago
14

The slope of the line is:

Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0
2/3. The line goes up 2 spaces and over 3 so rise over run gives you 2/3
You might be interested in
Paula has 4 bananas. She wants to divide each of them into 1/6 sections. How many 1/6's are there in 4 bananas?
k0ka [10]

Answer:

There are  24  1/6-banana sections in 4 bananas.

Step-by-step explanation:

Here we need to divide 4 bananas into 1/6 banana sections.  Dividing 4 bananas by 1/6 is equivalent to multiplying 4 bananas by 6/1:

(4)(6)

-------- = 24

   1

There are  24  1/6-banana sections in 4 bananas.

6 0
3 years ago
Diana ran a total of 9 3/4 miles over three days. She runs the same distance each day. How many miles did Diana run each day?
Natasha2012 [34]

Answer:

3 1/4

Step-by-step explanation:

4 0
3 years ago
A circle is defined by the equation x2 + y2 + 8x + 22y + 37 = 0. What are the coordinates for the center of the circle and the l
inn [45]
We can say that:
8x = -2ax
8 = -2a
a = -4

22y = - 2by
22 = -2b
b = -11

37 = a² + b² - r²
37 = (-4)² + (-11)² - r²
r² = 16 + 121 - 37
r² = 100
r = 10

With all this information, we can say that:
The center of the circle is: (-4 ; -11)
and the radius of the circle is r = 10

P.S:
(a - x)² + (b-y)² = r²
a² - 2ax + x² + b² -2by + y² - r² = 0
x² + y² -2ax - 2by + a² + b² - r² = 0

6 0
3 years ago
HELP ASAP PLEASE
Stels [109]
Solution (1) using angles of sectors:

Area of A = pi r^2  x 90/360 = 4.9

Area of B = pi r^2 x 270/360 = 14.2 


Check:  Area of A/B = 4.9/14.72 = 1/3 (as given)

Solution (2) using given info:

Area of B + Area of A = area of circle

Area of B + 1/3 Area of B =  3.14 * (2.5)^2 = 19.625

4/3 Area of B = 19.625

Area of B = 3/4 * 19.625

Area of B = 14.72

Area of A = 1/3 * 14.72 = 4.9

There is more solutions to this problem , like polar coordinate integration , and so on. for more just request. 



8 0
3 years ago
Multiply 3xyz ^ 2 / 6y ^ 4 by 2y / x z ^ 4
Marat540 [252]

\dfrac{3xyz^2}{6y^4}=\dfrac{3}{6}\cdot\dfrac{xyz^2}{y^4}=\dfrac{1}{2}\cdot\dfrac{xz}{y^3}=\dfrac{xz}{2y^3}\\\\\\\dfrac{3xyz^2}{6y^4}\cdot\dfrac{2y}{xz^4}=\dfrac{xz^2}{2y^3}\cdot\dfrac{2y}{xz^4}=\dfrac{2}{2}\cdot\dfrac{xyz^2}{xy^3z^4}=1\cdot\dfrac{1}{y^2z^2}=\dfrac{1}{y^2z^2}

8 0
3 years ago
Read 2 more answers
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