3,200?? (it may not be right I'm sorry.)
Answer:
½ ln 3
Step-by-step explanation:
∫ sec²x / tan x dx
If u = tan x, then du = sec²x dx.
∫ du / u
ln|u| + C
ln|tan x| + C
Evaluate between π/4 and π/3.
ln|tan(π/3)| + C − (ln|tan(π/4)| + C)
ln|√3| + C − ln|1| − C
ln(√3)
½ ln 3
50 yards for 1 lap
50 yards x 18 laps = 900 total yards
now divide the amount he swam by the total amount he wants to swim:
738 / 900 = 0.82 = 82%
Answer is B
