All categories

2 years ago

I need help I really don’t understand it

Mathematics

2 answers:

FinnZ [79.3K]2 years ago

5 0

Answer:

A B and D

Step-by-step explanation:

Stells [14]2 years ago

4 0

Answer:

basically your looking at which ones are like idk how to explain it but so far i see A and E look correct maybe E and C

Step-by-step explanation:

You might be interested in

Use the quadratic formula to solve x^2+8x+9=0

Tju [1.3M]

None of your options, not via complete the square nor quadratic the formula.

Solve for x over the real numbers:
x^2 + 8 x + 9 = 0

x = (-8 ± sqrt(8^2 - 4×9))/2 = (-8 ± sqrt(64 - 36))/2 = (-8 ± sqrt(28))/2:
x = (-8 + sqrt(28))/2 or x = (-8 - sqrt(28))/2

sqrt(28) = sqrt(4×7) = sqrt(2^2×7) = 2sqrt(7):
x = (2 sqrt(7) - 8)/2 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 + 2 sqrt(7) giving 2 (sqrt(7) - 4):
x = 1/22 (sqrt(7) - 4) or x = (-2 sqrt(7) - 8)/2

(2 (sqrt(7) - 4))/2 = sqrt(7) - 4:
x = sqrt(7) - 4 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 - 2 sqrt(7) giving 2 (-sqrt(7) - 4):
x = sqrt(7) - 4 or x = 1/22 (-sqrt(7) - 4)

(2 (-sqrt(7) - 4))/2 = -sqrt(7) - 4:

Answer: x = sqrt(7) - 4 or x = -sqrt(7) - 4_____________________________________________________

Solve for x:
x^2 + 8 x + 9 = 0

Subtract 9 from both sides:
x^2 + 8 x = -9

Add 16 to both sides:
x^2 + 8 x + 16 = 7

Write the left hand side as a square:
(x + 4)^2 = 7

Take the square root of both sides:
x + 4 = sqrt(7) or x + 4 = -sqrt(7)

Subtract 4 from both sides:
x = sqrt(7) - 4 or x + 4 = -sqrt(7)

Subtract 4 from both sides:
Answer: x = sqrt(7) - 4 or x = -4 - sqrt(7)

4 0

2 years ago

Plz answer 100 points!!!!!

zlopas [31]

Answer:

$3x + ( - 2 - 3) = 19 \\ 3x+(- 5) = 10 + 9 \\ (1 + 2)x + ( - 5) = 19$

all values stand for 3x+(-5)=19

3x-5=19=> 3x=24=> <u>x=8</u>.

Three step requires another step, so it is difficult than two step process.

no, their is no limit to the number of steps it take to solve an equation.

Every number can be described as a sum/difference of two or three numbers.

7 0

2 years ago

ILL GIVE BRAINLEYyyyyyyy

Fed [463]

Answer:

2+10x-x^2, the last answer

Step-by-step explanation:

3 0

2 years ago

Directions: Using the digits 1 to 9, at most one time each, fill in the boxes to find the largest or smallest possible values fo

12345 [234]

9514 1404 393

Answer:

smallest: 8x -3 = 4; 1y +9 = 2. total = -49/8

largest: 1x -9 = 8; 2y +3 = 7. total = 19

Step-by-step explanation:

If we use variables to represent the box contents, we can write ...

ax -b = c
dy +e = f

Then the values of x and y are ...

x = (c +b)/a

y = (f -e)/d

For positive integer values of the variables, x will always be positive, and y may or may not be negative.

<h3>Smallest sum</h3>

For the sum to be the smallest, we must have x be as small as possible and the ratio (f-e)/d be as negative as possible.

x will be small for large 'a' and for (c+b) small. For y to be as negative as possible, we want 'd' and 'f' small and 'e' large. Best results are obtained for

8x -3 = 4 ⇒ x = 7/8
1y +9 = 2 ⇒ y = -7

For these coefficients, the sum is -6 1/8 = -49/8.

(note that the values of 'b' and 'c' can be swapped with no net effect)

<h3>Largest sum</h3>

For the sum to be the largest, we must have x as large as possible: (b+c) large and 'a' small. At the same time we must have y be positive and as large as possible: (f-e) positive and large, 'd' small. Best results are obtained for

1x -9 = 8 ⇒ x = 17
2y +3 = 7 ⇒ y = 2

For these coefficients, the sum is 19. Again, 'b' and 'c' can be swapped with no effect.

_____

<em>Additional comment</em>

These extreme values are verified by examination of the 60,480 possible permutations of the coefficients.

8 0

2 years ago

Read 2 more answers

Explain why the graph of a linear equation in the form of y=c is a horizontal line

xeze [42]

Let's say "c" is a constant, hmmmm any constant, for any value whatsoever of "x", "y" is always that constant, for example, say c = 3, thus y = 3, so a table for it will look like

$\bf \begin{array}{ccll}
x&y\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-\infty&3\\
-6&3\\
-5&3\\
-4&3\\
-3&3\\
-2&3\\
-1&3\\
0&3\\
1&3\\
2&3\\
3&3\\
4&3\\
5&3\\
6&3\\
+\infty&3
\end{array}$

now, if you plot those points, it'd looks like the picture below.

4 0

2 years ago