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iragen [17]
3 years ago
11

7x − 11 = 31 pls help me with this question

Mathematics
2 answers:
Katarina [22]3 years ago
7 0

Answer:

6

Step-by-step explanation:

add 11 to both sides, that cancels out so then your left with 7x=42, divide by 7 on both sides then you should get x=6

Sedbober [7]3 years ago
6 0

Hello, I hope you are having a wonderful day.

To solve this equation, we have to move all the constants (numbers) to the right, using the opposite operation.

7x-11=31

7x=31+11

7x=42

Divide both sides by 7 to isolate x:

x=6

Hence, x=6 (Answer)

Hope it helps!

Please mark brainliest.

~An emotional teen who helps others with joy

Good luck.

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Vlad1618 [11]

Answer:

Picture #1: x=16 ; y=10

Picture #2: x=21 ; y=15

Picture #3: x=18

Step-by-step explanation:

Picture #1:

(8x-14)* and (5x+34)* are Alternate Exterior Angle so they are congruent. And (8x-14)* and (5y+16)* are supplementary so they equal 180*.

Picture #2:

(6x+7)* and (3x-16)* are supplementary so they equal 180*. And (6x+7)* and (11y-32)* are Vertical Angles so they are congruent.

Picture #3:

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6 0
3 years ago
322/14 .....plzzzzzzzzzzzzzzzzzzzzzzz
DIA [1.3K]

23 is the answer 322 divided by 14 is 23

3 0
3 years ago
Read 2 more answers
Write an inequality for the graph. Then, in words, describe all the values of that make the inequality true.
kow [346]
-3 > x

The values that make this inequality true are those that are less than -3. The inequality does not include -3.
7 0
2 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
You make a time capsule with your friends. Find the surface area of the shape pictured. Use 3.14 to approximate pi.
Orlov [11]

Answer: 1,475.8mm^{2}

Step-by-step explanation:

1. If you join the top part and the bottom part of the figure, you obtain a sphere. Then, you must apply the formula for calculate the surface area of a sphere:

SA_s=4r^{2}(3.14)

Where r is the radius (r=\frac{10mm}{2}=5mm)

2. Then:

SA_s=4(5mm)^{2}(3.14)=314mm^{2}

3. The formula for calculate the suface area of the red part, which is a cylinder, is:

SA_c=2(3.14)(r)(h)

Where h is the height (h=32mm)

4. Then:

SA_c=2(3.14)(5mm)(32mm)=1,004.8mm^{2}

5. So, the total surface area is:

SA_t=314mm^{2}+1,004.8mm^{2}=1,318.8mm^{2}

6 0
3 years ago
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