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Phantasy [73]
2 years ago
6

LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)

Mathematics
2 answers:
klasskru [66]2 years ago
5 0

\huge \bf༆ Answer ༄

Let's solve ~

\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }

\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times   3{k}^{4} }

\qquad \looparrowright \sf - 2 \times 2 {}^{3}  \times  {k}^{2}   \times \sqrt{3}

\qquad \looparrowright \sf  - 16 {k}^{2}  \sqrt{3}

Hence, the correct choice is D

givi [52]2 years ago
4 0
Square root of 192 can be simplified to
8 sqrt(3)
square root of k^4 can be simplified to
k^2
multiply that and the -2 to get:
-16k^2 sqrt(3)
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A cyclist estimates that he will bike 80 miles this week. He actually bikes 75.5 miles. What is the percent error of the cyclist
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Answer:

<em>The percent error of the cyclist's estimate is 5.63%</em>

Step-by-step explanation:

<u>Percentages</u>

The cyclist estimates he will bike 80 miles this week, but he really bikes 75.5 miles.

The error of his estimate in miles can be calculated as the difference between his estimate and the real outcome:

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To calculate the error as a percent, we divide that quantity by the original estimate and multiply by 100%:

Error% = 4.5 / 80 * 100 = 5.625%

Rounding to the nearest hundredth:

The percent error of the cyclist's estimate is 5.63%

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