15. 10 cm, 10 cm, V200 cm : Right Angled Triangle
16. 9 in., 16 in., 25 in. : Not a right angled triangle
Step-by-step explanation:
In order to check whether the given sides form a right angled triangle, we check if the sum of squares of two shorter sides is equal to the square of third longest side.
So
<u>15. 10 cm, 10 cm, V200 cm</u>

<u>The triangle is a right angled triangle.</u>
<u>16. 9 in., 16 in., 25 in.</u>
Here
a = 9 in
b=16 in
c=25 in
So,

<u>The given triangle is not a right angled triangle.</u>
Keywords: Triangle, Right angled Triangle
Learn more about triangle at:
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The value of m ∠ RPS is 64. 7°
<h3>What are collinear angles?</h3>
Collinear angles are angles formed when three or more points lie on the same straight line.
Note that angles on a straight line sum up to 180 degrees.
From the diagram given, we can see that the angles are collinear angles and thus sum up to 180 degrees;
- m ∠QPS = 88°
- m ∠ RPS = 5x + 34°
- m ∠ QPR = 8x + 15°
m ∠QPS + m ∠ RPS + m ∠ QPR = 180°
88° + 5x + 34° + 8x + 15° = 180
collect like terms
5x + 8x = 180 - 137
Add like terms
13x = 43
Make 'x' the subject of formula
x = 43/ 7
x = 6. 14
m ∠ RPS = 5x + 34 = 5 ( 6. 14) + 34 = 30. 7 + 34 = 64. 7°
Thus, the value of m ∠ RPS is 64. 7°
Learn more about collinear points here:
brainly.com/question/3307641
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24) -10 to 25
25) 42
26) to much
27) also too much
don't get mad, this was only for 13 points so that's on you
240 centimeters why because i need point I don’t rlly know
2)
P(4,-4) -->(-4, 7)
4 - 8 = -4 -------->left 8
-4 + 11 = 7 -------->up 11
Answer: left 8; up 11
3)
C(3,-1) , left 4 up 1
3 - 4 = -1 -------->left 4
-1 + 1 = 0 -------->up 1
a)
(x , y) -->(x - 4 , y +1)
C(3, -1) -->C'(-1 , 0)
b)
(x , y) --> (x - 4, y + 1); (-1 , 0)