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Ivanshal [37]
3 years ago
8

John wants to gain weight for his wrestling team so he can compete in a different weight class. He currently weighs 187 pounds,

and is gaining weight at a rate of 1.5 pounds per week. Which equation below models this situation * number of weeks y = total weight (pounds )
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

The equation would be 1.5w + 187 = y.

Step-by-step explanation:

1.5 lbs per week

already 187

The variable would be 'w'

so 1.5w +187 = y

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3 Quiz
sertanlavr [38]

Answer:

y varies of directly as x. This means that the equation is of the form y=kx where k is any number.

Substituting y=12 when x=4, we get

12=k×4⇒k=3

Hence, the required equation is y=3x.

The value of y when x=5 is y=3x5=15.

Step-by-step explanation:

bro it will work ♥️

5 0
3 years ago
According to a survery 52% of the residents of a city oppose a downtown casino. Of these 52% about 5 out of 10 strongly oppose t
nignag [31]
<span>I need to satert by stating the questions clearly. Question A: What is the probability that a radomly selected resident opposes the casino and strongly opposes the casino? This is the joint probability of being opposed and being strongly opposes which is calculated as the product of both: 52/100 * 5/10 = 26/100 = 0.26. Question B. What tis the probability that a radomly selected resident opposes the casino and does not strongly oppose the casino. Again it is a joint probability, the product of being opposed and not being strongly opposed: 52/100 * 5/10 = 26/100 = 0.26. The are the same because the the half of the 52% oppose strongly and the other half does not. </span>
8 0
3 years ago
What is the distance between the two points (5,-2) and (-3,8)
bearhunter [10]
You need to use the distance formula
d =  \sqrt{ {(x - x)}^{2}  +  {(y - y)}^{2} }

\sqrt{ {(5 + 3)}^{2}  +  {( - 2 - 8)}^{2} }
so the distance between points (5,-2) and (-3,8) is
2 \sqrt{41}
which won't simplify so it stays as is
4 0
3 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
4 years ago
Jen has read 4/5 of a book. The next day she read 2/3 of what she had left. What fraction of the book is left to read?
Nostrana [21]

Answer:

1/15

Step-by-step explanation:


3 0
3 years ago
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