Question

Please help me!!!! I will try to give brainliest!!!

Answer 1

Answer:

refer to this attachment

thank you

Answer 2

Answers:

Starting inequality: $10(x+0.75) \le 50$

Ending inequality:  $x \le 4.25$

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Work Shown:

x = amount spent per bag, ignoring the bag fee

x+0.75 = amount per bag including bag fee

10(x+0.75) = total amount spent on the ten bags

This amount cannot be more than $50. This means 50 dollars is the highest we can go, aka the ceiling value.

That means we'd write $10(x+0.75) \le 50$ as one possible starting inequality.

Let's solve for x

$10(x+0.75) \le 50\\\\10x+7.5 \le 50\\\\10x \le 50-7.5\\\\10x \le 42.5\\\\x \le 42.5/10\\\\x \le 4.25$

The most he can spend on the items for any single bag is $4.25, which is ignoring the $0.75 fee

If we tack that fee on, then he spends 4.25+0.75 = 5 dollars per bag and ten of such bags leads to 5*10 = 50 dollars total. The answer is confirmed.