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3 years ago

For each scenario below, choose the graph that gives the best representation.

Mathematics

1 answer:

kvv77 [185]3 years ago

8 0

The graph that gives the best representation of the scenario is: option 1 (A).

<h3>Graph of Distance vs Time</h3>

A typical graph of distance vs time shows the distance covered as against time.
If the graph shows a line that slopes upwards, it implies movement from a spot, if it shows an horizontal line, it implies a rest.

The first graph is the correct one that best represents the scenario because it starts at the point of origin (0, 0), which means the bird covers not distance at zero time when it is still at its nest.

As the bird flies, distance increases with time till it stopped at a point to eat.. This is represented by horizontal line, meaning time increased but distance from the nest remains the same.

The upward slope from the spot represents the further distance the bird is flying in search for more food.

Therefore, the graph that gives the best representation of the scenario is: option 1 (A).

Learn more about distance vs time graph on:

brainly.com/question/18655388

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Let f(x)=7x-13. Find f^-1(x).

vitfil [10]

Ok but allow my humble self to use $y$ instead of $f(x)$ .

We have,

$y=7x-13$

If you wanna know what the inverse is swap the values of x and y,

$x=7y-13$

And now solve for y,

$x+13=7y\implies\boxed{y=f^{-1}(x)=\frac{x+13}{7}}$ .

Hope this helps.

5 0

3 years ago

Read 2 more answers

ZABC and ZQRS are supplementary angles.

Leno4ka [110]

Answer:

Solution given:

<ABC and <QRS are supplementary angles.

<ABC = 91°

we have

<ABC +<QRS=180°[supplementary]

<QRS=180°-91°=89°

m<QRS=89°

8 0

3 years ago

Read 2 more answers

Part 1. Please show work. Please assist me with these math problems.

Vitek1552 [10]

Answer: 1) 2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

2) 2,490,924

3) Neither

<u>Step-by-step explanation:</u>

$S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784$

$\sum^8_{k=1}S_k\\\\=S_1+S_2+S_3+S_4+S_5+S_6+S_7+S_8\\\\= 2,490,924\\$

Neither

Not arithmetic because the difference between each of the terms is not the same.

S₂ - S₁ S₃ - S₂ S₄ - S₃

3 - 2 = 1 4 - 3 = 1 9 - 4 = 5

Not geometric because the ratios between each of the terms is not the same.

$\dfrac{S_2}{S_1}=\dfrac{S_3}{S_2}\qquad \rightarrow \dfrac{3}{2}=\dfrac{4}{3}\qquad \rightarrow \text{cross multiply to get}: 9\neq 8$

8 0

3 years ago

Simplify the expression below:

kifflom [539]

Answer:

C. -7x^2 - 28

Step-by-step explanation:

Firstly simplify the bracket before doing anything;

4x(3x - 7) = 12x^2 - 28x

then go back to the question and substitute the expression(12x^2 - 28x) on the bracket and then work out the question;

12x^2 - 28x -19x^2...then group the values with the same exponent of x,

(12x^2 - 19x^2) - 28x

; -7x^2 - 28x

6 0

3 years ago

In the first event, the eighth graders are running a baton relay race with three other classmates. The teams top speed for each

chubhunter [2.5K]

Answer:

The best time is 56.81 seconds

Average leg time is 58.3825 seconds

Step-by-step explanation:

Here, we want to start by stating the team’s best time for the race

The team’s best time for the race is the smallest time spent on a lap

From the times given, the best time is 56.81 seconds

Now, we want to calculate the average time

We simply add up all these and divide by count

Mathematically, that will be;

(56.81 + 59.22 + 57.39 + 60.11)/4 = 58.3825 seconds

8 0

3 years ago