The rule of thumb for this kind of problem is that you must first determine the limiting variable in your situation. We know that for a single sandwich, 50 grams bread greatly exceeds the 9 grams of ham requirement. We also know that there will be a greater supply of ham since 1 kg is relatively close in amount to 1.2 kg. This means that we only need to look at the bread for calculation purposes. We can get the total number of sandwiches to be 1200 / 50 = 24 sandwiches.
B. Sometimes because in learned that it isn't always that way.
Answer:
Mark answer C and D as correct
Step-by-step explanation:
Recall that a bisector cuts the side in two equal segments, then KH has to be half of 136 that is KH = 68
Also KHZ and HLZ are right angle triangles that share the same hypotenuse, so they are congruent triangles, which means that HL must equal KH and therefore the full side HJ must be 68 times 2 = 136
Answer:
Option C is correct.
Step-by-step explanation:
We need to find reference angle and signs of sinФ, cosФ and tanФ
We know that 
is equal to 150°
and 150° is in 2nd quadrant.
So, Ф is in 2nd quadrant.
And In 2nd quadrant sine is positive, while cos and tan are negative
The reference angle Ф' is found by: π - Ф
=> Ф = 5π/6
so, Reference angle Ф' = π - 5π/6
Ф' = 6π - 5π/6
Ф' = π/6
So, Option C Θ' = pi over 6; sine is positive, cosine and tangent are negative is correct.
Answer:
Yes
Step-by-step explanation:
All rhombuses are parallelograms, but not all parallelograms are rhombuses. All squares are rhombuses, but not all rhombuses are squares. The opposite interior angles of rhombuses are congruent. Diagonals of a rhombus always bisect each other at right angles.
