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blondinia [14]
2 years ago
10

REALLY need help solving this

Mathematics
2 answers:
Solnce55 [7]2 years ago
7 0

Answer:

2744m^3

Step-by-step explanation:

14*14*14=2744m^3

Alex73 [517]2 years ago
6 0
V = 2744 m³
Volume of cube= length³= l³= 14³= 2744 m³
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A random sample of 10 chocolate energy bars of a certain brand has, on average, 230 calories per bar, with a standard deviation
Troyanec [42]

Answer:

The confidence interval for the true mean calorie content is

215

Step-by-step explanation:

In this problem we know the mean and standard deviation fo the sample, so we can compute the CI like this:

\bar{x}-t*s/\sqrt{n}< \mu

We need to determine t for 10-1=9 degrees of freedom and 99% confidence level. We look up in the t-table and the value for t is 3.2498.

Then we can calculate the limits of the CI:

\bar{x}-t*s/\sqrt{n}< \mu

5 0
4 years ago
A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su
zaharov [31]

Answer:

After 1st year, the age distribution will be

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

x_1 = A \cdot x

x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = A \cdot x_1

x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

4 0
4 years ago
Find the measure of angle Z
ira [324]

Answer:

∠Z ≈ 12°

Step-by-step explanation:

Using the Sine Rule in ΔXYZ

\frac{x}{sinx} = \frac{z}{sinz}, that is

\frac{48}{sin96} = \frac{10}{sinz} ( cross- multiply )

48 × sinZ = 10 × sin96° ( divide both sides by 48 )

sinZ = \frac{10sin96}{48}

Z = sin^{-1} ( \frac{10sin96}{48} ) ≈ 12°

8 0
4 years ago
Fred went to his local zoo that featured 6 whale exhibits. If the zoo features 15 exhibits in total, then what percent of the zo
lorasvet [3.4K]

Answer:40%

Step-by-step explanation:

Given

The zoo featured 6 whales exhibits

There are 15 exhibits in total

Percentage of Zoo's exhibits featuring whales

\Rightarrow \dfrac{6}{15}\times 100=40\%

7 0
3 years ago
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Bad White [126]
Answer: 5 to the right and 2 down (top right corner)

Start at the "birds" point. Moving 5 units to the right will get you directly above the "reptiles" point. Then move 2 units down to actually get to the "reptiles" point.
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4 years ago
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