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djverab [1.8K]
3 years ago
8

Triangles AOC and BOD are congruent by SAS. Therefore, and these lengths can be found using the . Because this is the unit circl

e, the coordinates of points A, B, and D are equal to cosine and sine of α + β, α, and –β, respectively. Write expressions for the lengths and set them equal. Rewrite cos(-β) and sin(-β) using the identities before squaring both sides of the equation. Simplifying the resulting expressions involving cosine and sine of α, β, and α + β requires using the identity. When simplified, the equation becomes cos(α + β) = cos(α)cos(β) - sin(α)sin(β).
Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Based on the information given, it can be seen that Triangles AOC and BOD are congruent by SAS. Therefore, AC = BD.

<h3>What is a distance formula for a triangle?</h3>

It should be noted that the lengths can be found by using the <u>distance formula</u>. This is used to find the distance between two points. In this case, rewrite cos(-β) and sin(-β) using the even and odd identities before squaring both sides of the equation.

Lastly, simplifying the resulting expressions involving cosine and sine of α, β, and α + β requires using the <u>Pythagoras identity.</u>

Learn more about triangles on:

brainly.com/question/17335144

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[38]

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A square coaster has a side length of 512 feet on each side.
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3 years ago
Rationalise the denominator of: (√3 + √2)/(√3-√2) = ?<br>​
krok68 [10]

Step-by-step explanation:

<h3><u>Given</u><u>:</u><u>-</u></h3>

(√3+√2)/(√3-√2)

<h3><u>To </u><u>find</u><u>:</u><u>-</u></h3>

<u>Rationalised</u><u> form</u><u> </u><u>=</u><u> </u><u>?</u>

<h3><u>Solution</u><u>:</u><u>-</u></h3>

We have,

(√3+√2)/(√3-√2)

The denominator = √3-√2

The Rationalising factor of √3-√2 is √3+√2

On Rationalising the denominator then

=>[(√3+√2)/(√3-√2)]×[(√3+√2)/(√3+√2)]

=>[(√3+√2)(√3+√2)]×[(√3-√2)(√3+√2)]

=>(√3+√2)²/[(√3-√2)(√3+√2)]

=> (√3+√2)²/[(√3)²-(√2)²]

Since (a+b)(a-b) = a²-b²

Where , a = √3 and b = √2

=> (√3+√2)²/(3-2)

=> (√3-√2)²/1

=> (√3+√2)²

=> (√3)²+2(√3)(√2)+(√2)²

Since , (a+b)² = a²+2ab+b²

Where , a = √3 and b = √2

=> 3+2√6+2

=> 5+2√6

<h3><u>Answer:-</u></h3>

The rationalised form of (√3+√2)/(√3-√2) is 3+2√6+2.

<h3><u>Used formulae:-</u></h3>

→ (a+b)² = a²+2ab+b²

→ (a-b)² = a²-2ab+b²

→ (a+b)(a-b) = a²-b²

→ The Rationalising factor of √a-√b is √a+√b

8 0
3 years ago
Explain the different ways it is possible to add two rational numbers and get a negative number
snow_lady [41]
<u><em>Answer:</em></u>
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<u><em>Explanation:</em></u>
<u>In order to add two rational numbers and get a negative value, one of two scenarios should occur:</u>
<u>1- both numbers are negative.</u>
In this case, the answer would definitely be negative as the two numbers are originally negative
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<u>2- negative number is greater than the positive number</u>
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\frac{-5}{6} +  \frac{2}{6} =  \frac{-3}{6}

Hope this helps :)
5 0
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