The solution set for 2x +3 (5-3x) = 7(5-3)
1 answer:
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$\implies 2^{2x}-2\cdot5^{2x}-(2^x)(5^x)>0$
let $2^x=a$ and $5^x=b$
So, $a^2-2b^2-ab>0$
divide by $b^2$, ($b^2>0$)
$\implies \left(\frac ab\right)^2-\left(\frac ab\right) -2>0$
this is a quadratic, in $\left(\frac ab\right)$, let it be $x$
So, $x^2-x-2>0$
Can you simplify it now?
Answer:
Step-by-step explanation:
Given that,
The radius of a circle, r = 5 m
The central angle is 180 degrees
We need to find the area of a sector of a circle.
The formula for the area of sector of a circle is given by :
So, the area of the sector of a circle is .