PLEASE HELPPPPPP

Mathematics

1 answer:

Ulleksa [173]2 years ago

6 0

Answer:

ID => 657 824 8085

PA => 12345

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Find the measure of angle x in the figure below A.35° B.47° C.51° D.62°

Dafna11 [192]

First of all, we know that a line is 180°. This means if we add the angles of 61°, 57°, and angle y, we should get 180°.

$\sf 61\textdegree +57\textdegree+y=180\textdegree$

Simplify:

$\sf 118\textdegree +y=180\textdegree$

Subtract 118° to both sides:

$\sf y=62\textdegree$

We also know that all three angles of a triangle add up to 180°. So we have:

$\sf 67\textdegree+62\textdegree +x=180\textdegree$

Simplify:

$\sf 129\textdegree +x=180\textdegree$

Subtract 129° to both sides:

$\sf x=\boxed{\sf 51\textdegree}$

5 0

3 years ago

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Angle 0 lies in the second quadrant and sin 0 = 3/5 cos= coy =

Elza [17]

Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
$\sin B=\frac{opposite}{hypotenuse} = \frac{3}{5}$ and
$\cos B = \frac{adjacent}{hypotenuse} = \frac{4}{5}$ .

Since O lies in second quadrant $\cos O\ \textless \ 0$ and
$\cos O= -\cos B =- \frac{4}{5}$ .
Answer: $\cos O=- \frac{4}{5}$ .

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3 years ago

If there are 30 adults at a party and 21 kids at a party what is the fraction of adults at the party

Arisa [49]

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i think its 70 percent maybe

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Neporo4naja [7]

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