The answer is 5
Because if x = 2 then you just do 2+3 which is 5
(26X) - 34 = 18
26X = 18 + 34 = 52
X= 52 / 26 = 2
Let
be the coordinates of point P.
The distance from the x-axis is exactly the y coordinates of point P.
The distance from the point (3,-3) is given by
![\sqrt{(x-3)^2+(x+3)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x-3%29%5E2%2B%28x%2B3%29%5E2%7D)
So, we want
![y = 3\sqrt{(x-3)^2+(y+3)^2}](https://tex.z-dn.net/?f=y%20%3D%203%5Csqrt%7B%28x-3%29%5E2%2B%28y%2B3%29%5E2%7D)
We can square both sides to get
![y^2=9((x-3)^2+(y+3)^2)](https://tex.z-dn.net/?f=y%5E2%3D9%28%28x-3%29%5E2%2B%28y%2B3%29%5E2%29)
Expanding the squares, we have
![y^2=9(x^2-6x+9+y^2+6y+9) = 9(x^2+y^2-6x+6y+18)=9x^2+9y^2-54x+54y+162](https://tex.z-dn.net/?f=y%5E2%3D9%28x%5E2-6x%2B9%2By%5E2%2B6y%2B9%29%20%3D%209%28x%5E2%2By%5E2-6x%2B6y%2B18%29%3D9x%5E2%2B9y%5E2-54x%2B54y%2B162)
So, the final equation is
![y^2=9x^2+9y^2-54x+54y+162 \iff 9x^2+8y^2-54x+54y+162=0](https://tex.z-dn.net/?f=y%5E2%3D9x%5E2%2B9y%5E2-54x%2B54y%2B162%20%5Ciff%209x%5E2%2B8y%5E2-54x%2B54y%2B162%3D0)
Answer:
68 and 7
Step-by-step explanation:
Answer:
![(x, y) \rightarrow (-x, -y)](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%5Crightarrow%20%28-x%2C%20-y%29)
Step-by-step explanation:
Rotation of any point in the form of (x, y) about the origin O through 180 degree in anticlockwise or counterclockwise direction, it will takes the new position (-x, -y)
i.e,
The rule of rotation about the origin through 180 degree is given by:
![(x, y) \rightarrow (-x, -y)](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%5Crightarrow%20%28-x%2C%20-y%29)
For example:
Let the point A(-4, 6) rotate by the rule
then;
![A(-4, 6) \rightarrow (4, -6)](https://tex.z-dn.net/?f=A%28-4%2C%206%29%20%5Crightarrow%20%284%2C%20-6%29)
⇒the coordinate of image of the point A is, (4, -6)
Therefore, the rule represents
is, ![(x, y) \rightarrow (-x, -y)](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%5Crightarrow%20%28-x%2C%20-y%29)