Answer:
√33
x = -5/2 ± ---------
2
Step-by-step explanation:
Through completing the square, we get:
x^2 + 5x + (5/2)^2 - (5/2)^2 - 2 = 0, or
(x + 5/2)^2 - 25/4 - 2 = 0.
This simplifies to
(x + 5/2)^2 = 33/4
Taking the square root of both sides yields:
x + 5/2 = ±√(33/4), which can be solved explicityl for x:
√33
x = -5/2 ± ---------
2
Answer: 0
Step-by-step explanation:
Answer: A
Step-by-step explanation: I say this becauase they have 10x meaning this one comes first so c and d are out and b didnt make any sense so the answer is A. I hope this helped
When the penny hits the ground, h will = 0.
So: Set h(t) = 0 = -4.9t^2 + 0t + 150 m
Then 4.9t^2 = 150, and so t^2 = sqrt(150 / 4.9) = plus or minus 5.53 sec.
We can use only the positive root, as we're measuring time.
t = 5.5 sec (answer)
Answer:
0.6915
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 88, \sigma = 4[/ex]What is the probability that a single car of this model emits more than 86 mg/mi of NOX + NMOG?This is 1 subtracted by the pvalue of Z when X = 86. So[tex]Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=%5Cmu%20%3D%2088%2C%20%5Csigma%20%3D%204%5B%2Fex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EWhat%20is%20the%20probability%20that%20a%20single%20car%20of%20this%20model%20emits%20more%20than%2086%20mg%2Fmi%20of%20NOX%20%2B%20NMOG%3F%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EThis%20is%201%20subtracted%20by%20the%20pvalue%20of%20Z%20when%20X%20%3D%2086.%20So%3C%2Fp%3E%3Cp%3E%5Btex%5DZ%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
has a pvalue of 0.3085
1 - 0.3085 = 0.6915
The answer is 0.6915
