Can someone help me with this question and please show me how you got them thanks in advance

17) Solve the system as matrix equations using inverses. 17) A company produces three models of MP3 players, models A, B, and C.

Vinvika [58]

Answer:

Model A=30, Model B: 20, Model C: 45

Step-by-step explanation:

Let x be the amount of type A mp3 produced, and the amount of model B mp3's produced and z the amount of model C mp3 produced.

Since in total there are 303 hours for electronics work, then:

$3.2x+5.4y+2.2z=303$

Since in total there are 393 hours for assembly, then:

$2.8x+2.4y+5.8z=393$

Since in total there are 416 hours for quality assurance, then:

$4.4x+3.4y+4.8z=416$

Then, the linear system associated to the problem is

$3.2x+5.4y+2.2z=303\\2.8x+2.4y+5.8z=393\\4.4x+3.4y+4.8z=416$

with coefficient matrix $A=\left[\begin{array}{ccc}3.2&5.4&2.2\\2.8&2.4&5.8\\4.4&3.4&4.8\end{array}\right]$ and vector of constant terms $b=\left[\begin{array}{ccc}303\\393\\416\end{array}\right]$

Since the determinant of A is equal to 36.704 then A is invertible.

Then for solve the system $Ax=b$ , is enough find the inverse of A and operate

$Ax=b\\A^{-1}Ax=A^{-1}b\\x=A^{-1}b$

Using Octave we obtain that

$A^{-1}=\left[\begin{array}{ccc}-0.22&-0.50 &0.71\\0.33&0.15&-0.34\\-0.028& 0.35&-0.20\end{array}\right]$

Then

$x=A^{-1}b=\left[\begin{array}{ccc}30\\20\\45\end{array}\right]$

This means that 30 mp3's of model A, 20 of model B and 45 of model C must be produced

8 0

3 years ago

What is green and makes holes

Novosadov [1.4K]

Answer:A drill pickle

Step-by-step explanation:

6 0

3 years ago

Verify which of the following are identities.

-Dominant- [34]

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

Note that

$\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)$

You can confirm it:

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

Therefore

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

$8\sec(\theta)=8\csc(\theta)$

<h2>It is not an Identity</h2>

Let's the second one

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

3 0

3 years ago

How is 21\30 bigger then 2\3

strojnjashka [21]

By reducing 21/30 you dived 21 and 30 by 3 and you will get 7/10. Is 7/10 larger than 2/3? If we put these fractions in decimal form we will see 7/10 turns into 0.7 and 2/3 turns into 0.667. So the answer is 21/30 is larger than 2/3.

3 0

3 years ago

Roger manages an ice cream stand. He keeps track of how many minutes each customer stands in line.

aalyn [17]

0.5 = 2
0.75 = 2
1.0 = 3
1.25 = 4
1.5 = 5
2.0 = 2
2.25= 1
2.5 = 1

You should always count the numbers you used to make sure the total matched the total number of data. In this case, there are 20 numbers, and the total is also 20.

5 0

3 years ago

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