Let y = 12 e^2x
e^2x = y/12
Taking
[email protected]ln e^2x = ln (y/12)
2x = ln (y/12)
x = (1/2) ln (y / 12)
so the inverse h-1(x) = (1/2) ln ( x / 12)
Hello from MrBillDoesMath!
Answer:
108 cm^2
Discussion:
The area of the logo =
area of Trapezoid on top (I) + area of triangle on bottom (II)
I = (1/2) h ( b1 + b2) h = altitude, b1, b2 = bases
= (1/2) 6 ( 6 + 12)
= (1/2) 6 ( 18)
= 54
II = (1/2) b h
= (1/2) (12) ( 15 - 6) => altitude of triangle = 15 - 6 NOT (1/2) 15
= 54
I + II= 54 + 54 = 108
Thank you,
MrB
Answer:
Step-by-step explanation:
The system of equations is given as
y=x^2-5x+7 - - - - - - - - - - 1
y=2x+1 - - - - - - - - - - - - - - 2
We would equate equation 1 to equation 2, it becomes
x^2-5x+7 = 2x+1
x^2-5x+7- 2x - 1 = 0
x^2-5x+7- 2x - 1 = 0
x^2 - 5x - 2x + 7 - 1 = 0
x^2 - 7x + 6 = 0
We would use the factorization method of solving quadratic equations.
x^2 - 6x - x + 6 = 0
x(x - 6) - 1(x - 6)
(x - 6)(x - 1) = 0
x - 6 = 0 or x - 1 = 0
x = 6 or x = 1
Substituting both values of x into equation 2, it becomes
For x = 6,
y=2×6 + 1 = 12 + 1 = 13
y = 13
For x = 1,
y=2 × 1 +1 = 2 + 1 = 3
y = 3
Answer:
10 is unbiased
11 is biased
Step-by-step explanation:
10 is unbiased
11 is biased
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Answer:
B
Step-by-step explanation:
