Answer:
a 4x + 10 i think
Step-by-step explanation:
<u>Prime factors:</u>
<u>Common factors of the two numbers: </u>
Possible number of students as above
Answer: 0.82
The probability of the computer not containing neither a virus nor a worm is expressed as P(∩) , where P() is the probability that the event V doesn't happen and P() is the probability that the event W doesn't happen.
P()= 1-P(V) = 1-0.17 = 0.83
P()=1-P(W) = 1-0.05 = 0.95
Since and aren't mutually exclusive events, then:
P(∪) = P() + P() - P(∩)
Isolating the probability that interests us:
P(∩)= P() + P() - P(∪)
Where P(∪) = 1 - 0.04 = 0.96
Finally:
P(∩) = 0.83 + 0.95 - 0.96 = 0.82
The probabilities of all possible outcomes in a distribution must sum to 1.