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olga_2 [115]
3 years ago
8

A garden center is running a special on houseplants. A selection of any 2 plants cost $7. If a designer buys 22 plants for new h

omes, how much does the designer spend on plants?
Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

77

Step-by-step explanation:

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Two trains left the station at the same time, one heading due east at 40 miles per hour and the other heading due west at 50 mil
Ivan

well you have to see how far they have gotten after 4 hours. so 4*40=160 50*4=200. since it was opposite directions you add. so 160+200=360.

3 0
3 years ago
Scores turned in by an amateur golfer at a golf course during 2017 and 2018 are as follows.
SSSSS [86.1K]

Answer:

For 2017 Season:

Mean = 75

Standard deviation = 2.07

For 2018 Season:

Mean = 75

Standard deviation = 5.26

Step-by-step explanation:

The following formulas will be used in these calculations:

Mean = (sum of the values) / n

Variance = ((Σ(x - mean)^2) / (n - 1)

Standard deviation = Variance^0.5

Where;

n = number of values = 8

x = each value

For 2017 Season

Mean = (73 + 77 + 78 + 76 + 74 + 72 + 74 + 76) / 8 = 600 / 8 = 75

Variance = ((73-75)^2 + (77-75)^2 + (78-75)^2 + (76-75)^2 + (74-75)^2 + (72-75)^2 + (74-75)^2 + (76-75)^2) / (8-1) = 30 / 7 = 4.29

Standard deviation = Variance^0.50 = 4.29^0.5 = 2.07

For 2018 Season

Mean = (70 + 69 + 74 + 76 + 84 + 79 + 70 + 78) / 8 = 75

Variance = ((70-75)^2 + (69-75)^2 + (74-75)^2 + (76-75)^2 + (84-75)^2 + (79-75)^2 + (70-75)^2 + (78-75)^2) / (8-1) = 194 / 7 = 27.71

Standard deviation = Variance^0.50 = 27.71^0.5 = 5.26

4 0
3 years ago
14,800 at 6% compounded semiannually for 4 years.. I need to know the interest and the compound amount
Zepler [3.9K]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=
\begin{array}{llll}
\textit{original amount}\\
\textit{deposited}
\end{array}\to &\$14,800\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, meaning twice}
\end{array}\to &2\\

t=years\to &4
\end{cases}

now, that will give you "A", or the compounded amount

what's the interest earned?  well, subtract the original amount, the Principal, from A, A - P, and you'd be left with the earned interest

--------------------------------------------------------------------------------------------
\bf A=14,800\left(1+\frac{0.06}{2}\right)^{2\cdot  4}

6 0
3 years ago
Please answer it really need it!
melamori03 [73]

Answer:

C, sorry if it is wrong

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which line segment is a chord of o C in the diagram below?
Sholpan [36]

Answer:

A. AB

Step-by-step explanation:

line segment AB is a chord.

4 0
3 years ago
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