2 years ago

Pa sagot po please maraming salamat po

Mathematics

1 answer:

Oksanka [162]2 years ago

8 0

Oh wow wow yeah it’s good enough that you didn’t understand

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1. Evaluate the expression when x=2, y = 3, and z= -9:

kupik [55]

Answer:

-7

Step-by-step explanation:

substitute the given values into the expression

xy-x

(-2 times 3)-1

-6 - 1 = -7

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3 years ago

Given the following triangles, what additional information is required in order to know that the triangles are congruent because

Soloha48 [4]

Answer:

The correct answer is : DCQ ( angle) = DCE (angle)

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4 years ago

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Evaluate the expression if m = – 4, n = 1, p = 2, q = –6, r = 5, and t = -2. |3r + 6m

fgiga [73]

Answer:

m=4,2=9, and r=. (Examples 1-6). 1. 3+ m 7. 2. z-m 5. | 3. 12r 2

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3 years ago

What is 1 times 1 plus 85 plus an extra 4

Elodia [21]

Answer: 90

Step-by-step explanation: 1 Multiplied By 1 Is 1 So If You Add 85 To It You Get 86 Add 4 To That You Get 90

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3 years ago

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Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

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3 years ago