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In-s [12.5K]
2 years ago
8

7. A game is played with 2 fair number cubes. One cube has faces numbered 1 through 6. The second number cube is numbered 4 thro

ugh 6, and each number is marked on two faces. If both cubes are tossed, what is the probability of rolling a 2 on the first cube and a 3 on the second cube?​
Mathematics
1 answer:
Marizza181 [45]2 years ago
8 0

Answer:

Less than two would be one.  Since there is only one of that, it would be 1/6th or 0.6666

Step-by-step explanation:

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Determine forms of exponential expressions please help
Irina-Kira [14]

Answer:

(36^t) / (6^(t^2)) is nonequivalent

(6^(t^2)) / (36^t) is equivalent

(6^(t^2)) * 36^t is nonequivalent

Step-by-step explanation:

We can use the exponential quotient law for this problem.

a^x / a^y = a^x - y

(6^(t^2)) / (6^2t) = (6^(t^2)) / (36^t)

4 0
2 years ago
What is the value of the expression shown?
faust18 [17]

Answer:

31

Step-by-step explanation:

3 0
2 years ago
The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take
Alex73 [517]

Answer:

It will take  <u><em>80 days</em></u>  for the bull calf to reach a weight of 500 kilograms.

Step-by-step explanation:

Given:

The weight of a bull calf is 388 kilograms.

Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.

Required weight which to be increased = 500 - 388 = 112 kilograms.

Rate of weight increase = 1\frac{2}{5}=\frac{7}{5}

                                        = 1.4\ kilograms.

Thus, the time required = \frac{required\ weight}{rate\ of\ weight}

                                        = \frac{112}{1.4}

                                        = 80.

<em>The time required   =    80 days</em>.

Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.

5 0
3 years ago
What is the volume of a cylinder with a height of 4xy^4 and a radius of 2x? (The formula fo
OLga [1]

Answer:

volume: \sf 16\pi x^3y^4

given:

  • height: \sf 4xy^4
  • radius: \sf 2x

<u>cylinder volume</u>:

\hookrightarrow \sf \pi r^2h

\hookrightarrow  \sf \pi (2x)^2(4xy^4)

\hookrightarrow  \sf \pi (4x^2)(4xy^4)

\hookrightarrow  \sf 16\pi x^3y^4

3 0
2 years ago
The students at a High School earned money for an international animal rescue foundation. 82 seniors earned an average $26.75 pe
Anon25 [30]

Answer: A. $16.13

Step-by-step explanation:

Total students = 82+74+96+99 =351

Sum of earnings of 82 seniors  = $26.75  x 82= $2193.5

Sum of earnings of 74 juniors  = $12.25 x 74 = $906.5

Sum of earnings of 96 sophomores  = $15.50  x 96 = $1488

Sum of earnings of 99 freshmen  =  $10.85 x 99 = $1074.15

Total earnings =  $2193.5  + $906.5+  $1488 +$1074.15

= $5662.15

(Total earnings) ÷ (Total students )

= $5662.15÷ 351

= $16.13

4 0
3 years ago
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