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In-s [12.5K]
2 years ago
8

7. A game is played with 2 fair number cubes. One cube has faces numbered 1 through 6. The second number cube is numbered 4 thro

ugh 6, and each number is marked on two faces. If both cubes are tossed, what is the probability of rolling a 2 on the first cube and a 3 on the second cube?​
Mathematics
1 answer:
Marizza181 [45]2 years ago
8 0

Answer:

Less than two would be one.  Since there is only one of that, it would be 1/6th or 0.6666

Step-by-step explanation:

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Answer:

  49

Step-by-step explanation:

When you look at the square of a binomial, you see ...

  (x +a)^2 = x^2 +(2a)x +a^2

The constant value (a^2) is <em>the square of half the x-coefficient</em>.

  (14/2)^2 = 49 . . . . the value to be added.

Adding 49 gives ...

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1 year ago
The frequency table below shows the antenna careers among the incoming class of first-year college students. Every student is ch
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To solve this you must use a proportion like so...

\frac{part}{whole} = \frac{part}{whole}

The total number of students that can be chosen are 4,663. This number will represent the whole of one fraction in the proportion. We want to know what percent probability out of these students are engineer, medical doctor/surgeon. This would be considered the part of this fraction. Sum the number of engineering students (615) with medical doctors/surgeons (723) to find this number

723 + 615 = 1,338 students that want to be an engineer or medical doctor/surgeon

Percent's are always taken out of the 100. This means that the other fraction in the proportion will have 100 as the whole and x (the unknown) as the part.

Here is your proportion:

\frac{1,338}{4,663} =\frac{x}{100}

Now you must cross multiply

1,338*100 = 4,663*x

133,800 = 4,663x

To isolate x divide 4,663 to both sides

133,800/4,663 = 4,663x/4,663

28.7 = x

This means that there is a 28.7% of a student with the intent of becoming an engineer or a medical doctor/surgeon to be chosen at random

Hope this helped!

~Just a girl in love with Shawn Mendes

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