Answer:
a) P(X<50)=0.9827
b) P(X>47)=0.4321
c) P(-1.5<z<1.5)=0.8664
Step-by-step explanation:
We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.
a) This means we have to calculate P(x<50).
We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

b) We have to calculatee P(x>47).
We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

c) If the value differs 1.5 standard deviations from the mean value, we have a z-score of z=1.5

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

Answer:
200000x 10x
Step-by-step explanation:
hope this helps
Answer:
8.0 seconds to the nearest tenth,
Step-by-step explanation:
h=-16t^2 +vt + c.
-16t^2 + 116t + 101 = 0
t = [ -116 + /- √(116^2 - 4*-16*101) ] / (-32)
t = (-116 +/- √19920) / (-32)
t = -0.79, 8.036 (we ignore the negative root)
The time in flight = 8.036 seconds.
Do you still need help with it I can help you?