Question

What is the line symmetry for the graph of y= -3x^2+12x-11

Answer 1

The answer to your question is x=2. what you want to do is find both the x values for your quadratic equation and then add them and divide by 2.

Answer 2

Answer:

The line of symmetry is x=2

Step-by-step explanation:

Given:$y=-3x^2+12x-11$

We are given a quadratic equation and to find the line of symmetry.

As we know the line of symmetry of parabola passes through the x value of vertex.

If vertex of parabola is (h,k) then equation of line of symmetry x=h

So, first we find the vertex of parabola.

For equation: $y=ax^2+bx+c$

$x=-\dfrac{b}{2a}$

For given equation, a=-3 and b=12

Therefore, $x=-\dfrac{12}{2(-3)}$

$x=2$

Hence, The line of symmetry of given parabola is x=2