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patriot [66]
3 years ago
5

Melanie invests $8800 in a new savings account which earns 4.6% annual interest, compounded daily. What will be the value of her

investment after 6 years?
Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

it would be valued at $11,597

Step-by-step explanation:

In this question, we are asked to calculate the value of an investment, 6 years on from now, given the annual interest , initial investment and time

Mathematically;

A = P(1+r/n)^nt

From the question, A = ?

P is initial investment = $8,800

r is rate = 4.6% = 4.6/100 = 0.046

n is number of times compounded = 365 since it is daily and we have 365 days in a year

t = time= 6 years

Now, we input these values into the equation;

A = 8,800 (1+ 0.046/365)^(365*6)

A = 8,800 (1+ 0.00012602739726)^2190

A = 8,800(1.00012602739726)^2190

A = $11,596.86

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What is the correct answer please need help
Oduvanchick [21]

Answer:

52 cm^2

Step-by-step explanation:

Solve by splitting the figures into 2 parts and finding their areas separately:

Rectangle:

8 × 5 = 40

Triangle:

1/2 × b × h = 1/2 × 8 × 3 = 4 × 3 = 12

Total: 40 + 12 = 52

6 0
3 years ago
Read 2 more answers
The sides of a rectangle have the ratio 7:2. its perimeter is 207cm.<br> Find the area
castortr0y [4]
X - unit of length
w,l - the sides of a rectangle

7 : 2 ⇒ 7x : 2x

Perimeter: P = 207cm
Perimeter: P = 2w + 2l

therefore: 2w + 2l = 207    |divide both sides by 2

w + l = 103.5 (cm)

w : l = 7 : 2 ⇒ w : l = 7x : 2x ⇒ w = 7x; l = 2x

subtitute

7x + 2x = 103.5
9x = 103.5    |divide both sides by 9
x = 11.5 (cm)

7x = 7 · 11.5cm = 80.5cm
2x = 2 · 11.5cm = 23cm

w = 80.5cm; l = 23cm

Area = wl

Area: A = 80.5cm · 23cm = 1851.5cm²
8 0
3 years ago
Two cruise ships leave the same port with a 35° angle between their path. Cruise A is traveling at 18 miles per hour and Cruise
GuDViN [60]

Answer:

20\:\mathrm{miles}

Step-by-step explanation:

After travelling two hours, the two cruise ships form a triangle. One of the legs  of this triangle will be the distance Cruise A travelled, and another will be the distance Cruise B travelled. We can find the distance they travel using:

s=\frac{d}{t}, d=s\cdot t

Cruise A is travelling at 18 miles per hour for 2 hours. Therefore, Cruise A has travelled:

d=s\cdot t=18\cdot 2=36\:\mathrm{miles}

Cruise B is travelling at 15 miles per hour for 2 hours. Therefore, Cruise B has travelled:

d=s\cdot t=15\cdot 2=30\:\mathrm{miles}

Because we are given the angle between these legs, we can use the Law of Cosines to find the third leg. The Law of Cosines is given by:

c^2=a^2+b^2-2ab\cos C, where a, b, and c are interchangeable. Let c represent the distance between the two cruises. We have:

c^2=36^2+30^2-2\cdot36\cdot30\cdot \cos 35^{\circ},\\c^2=426.63,\\c\approx \fbox{$20\:\mathrm{miles}$}(one significant figure).

8 0
2 years ago
Read 2 more answers
According to a report from a business intelligence company, smartphone owners are using an average of 22 apps per month. Assume
Ira Lisetskai [31]

Answer:

0.4332 = 43.32% probability that the sample mean is between 21 and 22.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

According to a report from a business intelligence company, smartphone owners are using an average of 22 apps per month.

This means that \mu = 22

Standard deviation is 4:

This means that \sigma = 4

Sample of 36:

This means that n = 36, s = \frac{4}{sqrt{36}}

What is the probability that the sample mean is between 21 and 22?

This is the p-value of Z when X = 22 subtracted by the p-value of Z when X = 21.

X = 22

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{22 - 22}{\frac{4}{sqrt{36}}}

Z = 0

Z = 0 has a p-value of 0.5.

X = 21

Z = \frac{X - \mu}{s}

Z = \frac{21 - 22}{\frac{4}{sqrt{36}}}

Z = -1.5

Z = -1.5 has a p-value of 0.0668.

0.5 - 0.0668 = 0.4332

0.4332 = 43.32% probability that the sample mean is between 21 and 22.

4 0
2 years ago
A modern deck of cards contains fifty-two cards (thirteen in each of four suits). The four suits are hearts, diamonds, clubs, an
levacccp [35]
Well since there are 13 cards per suit, you start off with 13 cards. then since there are 4 suits that are able to be used, but one of those 4 is the spades suit. so you have 3 6's that can be used besides the spades. so you are left with a total of 16 cards that fit the description.
4 0
2 years ago
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