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Dennis_Churaev [7]
3 years ago
9

PLEASE HELP 25 POINTS

Mathematics
2 answers:
kifflom [539]3 years ago
8 0

Answer:

a-b=10 b-c=12 a-c=10

horsena [70]3 years ago
3 0
A-b=10. b-c=12. a-c=10.
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(11x + 8) + (8x + 12) =27
Tju [1.3M]

Answer:

11x + 8 +8x +12 =27  (drop the parenthesis, there's no actual need for them)

19x +20 =27 (i combined like terms and then subtracted 20 from both sides)

19x = 7  (divide both sides by 19 to get x alone)

x= 7/19 or 0.36842105 (the answer)

Step-by-step explanation:

7 0
3 years ago
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This is hard please help!!!
liq [111]

Answer:

6 and 1/3

Step-by-step explanation:

the only thing gets reduced is the fraction part and 5 and 15 have common numbers in 5 5 goes into 5 one time and 5 goes into 15 3 times. so it's 6 1/3

4 0
3 years ago
What number is 44 % of 840
sattari [20]
It's 369.6 
(840X44)/100 = 369.6
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4 years ago
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PLEASE HELP!! WILL GIVE Points Using the known angle, what side is known? What side is unknown? Use opposite, adjacent, or hypot
ruslelena [56]

4.

known side: opposite (150m)

unknown sides: adjacent and hypotenuse

using Tan to find the distance from the tower's base to the key.

why do we use Tan to find the distance?

the tower creates an angle of 72 degrees with the ground, which will be called α, and it is 150m high from the ground which is opposite ∠α. (shown in picture). we can see that the distance from the base of the tower to the key is the adjacent of the ∠α.

Tan α =  opposite / adjacent

=> Tan 72° = 150 / x

=> x = 150 / Tan 72°

=> x = 48.73795443 m = ~48.7m

5.

4.

known side: opposite (150m)

unknown sides: adjacent and hypotenuse

using Sin to find the distance that the ant travelled.

why do we use Sinn to find the distance?

the tower creates an angle of 72 degrees with the ground, which will be called α, and it is 150m high from the ground which is opposite ∠α. (shown in picture). the ant travelled along the tower's body, which is the hypotenuse of the triangle, from the top until reaching the ground.

Sin α =  opposite / hypotenuse

=> Sin 72° = 150 / x

=> x = 150 / Sin 72°

=> x = 157.7193336 m = ~157.7m

6.

(using unrounded numbers to calculate because there is a small difference in results if using the rounded numbers)

c^2 = a^2 + b^2 (pythago)

157.7^2 = 150^2 + 48.7^2

24875.3882 = 24875.3882 (correct)

7 0
3 years ago
I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

=(2x^2+2x-3)+(-x+3)

Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

4 0
3 years ago
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