Find the vertex of G(x)=x^2+4 x

Mathematics

1 answer:

Masja [62]3 years ago

3 0

Answer:

(- 2, - 4 )

Step-by-step explanation:

The x- coordinate of the vertex is calculated as

x = - $\frac{b}{2a}$

g(x) = x² + 4x

with a = 1, b = 4 , then

x = - $\frac{4}{2}$ = - 2

Substitute x = - 2 into g(x) for corresponding y- coordinate

g(- 2) = (- 2)² + 4(- 2) = 4 - 8 = - 4

vertex = (- 2, - 4 )

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