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2 years ago

HELP PLEASE DUE IN A MINUTE

Mathematics

2 answers:

ANTONII [103]2 years ago

8 0

Answer:

i didn't understand question no 3 so..

Alex73 [517]2 years ago

5 0

Answer:

a. 11 b. 16 c. what is a number that when you multiply it by 6 and subtract 3 from the product, you get 69. A: 12

Step-by-step explanation:

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Which of the following could be the graph of y = –xn where n is odd?

mina [271]

Answer:

Step-by-step explanation:

I think you meant y = -x^n, where ^ denotes exponentiation.

If n is odd, the graph begins in Quadrant II and decreases through the origin into Quadrant IV. This is true of -x, -x^3, -x^5, and so on.

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3 years ago

Designing a Sprinkler System

Bogdan [553]

Answer: Its B

Step-by-step explanation:

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2 years ago

Read 2 more answers

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

How do you do the area and how to do it to the nearest tenth

lord [1]

You just put I line in the middle and you times high times base the do the other one then add your answers up that should be your finely answer

6 0

3 years ago

What is the value of 10 to the 6 power. A.10 B.600 C.1,000,000 D.6,000,000

Korolek [52]

The answer is C. 1,000,000

3 0

3 years ago