The distance of the object from the mirror is 3cm.
To calculate the distance of the object from the mirror, we make use of the mirror formula
<h3>Mirror formula</h3>
- 1/f = (1/u)+(1/v)............ Equation 1
Where:
- f = Focal length of the mirror
- v = image distance
- u = object distance.
Using the real is positive convention,
Given:
Substitute these values into equation 1 and solve for u
- 1/5 = (-1/10)+(1/u)
- 1/5+(1/10) = 1/u
- 1/u = (2+1)/10
- 1/u = 3/10
- u = 10/3
- u = 3.33
- u = 3 cm
Hence, The distance of the object from the mirror is 3cm.
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Answer:
B. the gravitational pull of the Sun
E. Earth's resistance to change in motion
Sediments that are scraped off the subducting plate usually builds up in an accretionary wedge.
<h3>What is an
accretionary wedge?</h3>
An accretionary wedge is also referred to as accretionary prism form and it can be defined as a mass of sediments that are scraped off an oceanic crust region, especially during subduction and build up at a continental crustal plate.
This ultimately implies that, sediments that are scraped off the subducting plate usually builds up in an accretionary wedge.
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Hey I don’t see the diagram.
The final two steps of Harry as described in the task content are very correct.
<h3>How to solve linear equation?</h3>
According to the task content;
- It follows that the final steps of Harry's evaluation of the linear equation cam be identified as follows;
16 + 2x - 11 = 9x + 5 - 7x
16 - 11 + 2x = 9x - 7x + 5
5 + 2x = 2x + 5
By cancelling out like terms of the variable; we have;
5 = 5
Therefore, the Harry's final two steps although in another form are very correct.
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