Answer: The sarcolemma generally maintains the same function in muscle cells as the plasma membrane does in other eukaryote cells. It acts as a barrier between the extracellular and intracellular compartments, defining the individual muscle fiber from its surroundings
Explanation:
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Explanation:
First during protein synthesis, transcription occurs in the nucleus, followed by translation within ribosomes. Then, newly synthesized proteins enter endoplasmic reticulum where they undergo folding and modification. Next, within the golgi body, the proteins are tagged; after,they are finally parceled into lysosomes. Finally, they can be exported out of the cell to fulfill various functions.
Further Explanation:
The endoplasmic reticulum is a membrane system within the cytoplasm that extends from the outer nuclear membrane. Apart from increasing the surface area within the cell, this continuous system also carries out protein folding, synthesis and transport. In the endoplasmic reticulum or ER, some sections called the smooth ER, do not contain ribosomes, and may contain lipids, enzymes, and other proteins. Other sections bound to ribosomes, are called the rough Er. As a protein destined for the endomembrane system is being synthesized by a ribosome, the first amino acids in the growing polypeptide chain act as a signal sequence. That signal sequence ensures that the ribosome binds to the outer membrane of the ER and that the protein enters the ER lumen. The proteins undergo major modifications and are packed into vesicles.
Golgi bodies are flat, disk-like membranous regions. Proteins traverse the organelle by first having their vesicles bind to the cis face or receiving end. Like a post office, the golgi complex, or golgi body recognizes specific signal sequences, targets and further modifies and packages these compounds into lysosomes for delivery to their final destination. Proteins here undergo peptide processing and glycosylation
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Answer:
Given:
Number of colonies on plate = 40
Amount of DNA used for transformation = 100ng
Volume of competent cells used = 100ul
Total volume = 1ml (1000ul)
Volume plated for growth = 200ul
The amount of cells transformed per 1 µg of DNA is called the transformation efficiency
(CFU is colony forming units) => (number of colonies on plate/ng of DNA plated) X 1000 ng/µg = CFU/µg of DNA
Amount of DNA used for plating = 100ng * (200/1000)
= 100ng * (1/5)
= 100/5 = 20ng
Efficiency calculation = 40 colonies / 20ng = 2 colonies/ng
(2 colonies/ng) * (1000 ng/µg) = 2000 CFU/ug DNA
Transformation efficiency = 2000 Transformants / ug DNA
= 2 x 10³ Transformants / ug DNA
Explanation:
Efficiency of transformation is highest in the 100 pg-1 ng range, so Low transformation efficiency could be because of high amount of DNA used for transformation.
