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3 years ago

5

29. The rectangular tank given below is 50cm by 40cm by 20cm and is filled with water. (W=50cm H=20cm L=40cm) . Find the volume

of the water (in cm) the tank. b). How many litres of water can the hold when it is full?

1 answer:

Rainbow [258]3 years ago

3 0

Answer:

volume = l×w×h

v= 40cm×50cm×20cm

v=40,000cm³

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Easy algebra question below first correct answer gets brainliest

Shalnov [3]

Answer:

10

Step-by-step explanation:

We solve using Pythagoras Theorem. Pythagoras Theorem is used to solve for the missing side of a right angled triangle.

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c² = a² + b²

c = √a² + b²

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From the above diagram, we are looking for c

c = ?

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Hence,

c = √6² + 8²

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Answer:

$V=186.1\ m^3$

Step-by-step explanation:

<u>Volume of a Pyramid</u>

The volume of a pyramid with base area Ab and height H is given by:

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If the base is a square of side length L, then its area is:

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4 years ago

the vertex of this parabola is at (5,5). when the x-value is 6, the y-value is -1. what is the coefficient of the squared in the

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Answer: OPTION D.

Step-by-step explanation:

The vertex form of a quadratic function is:

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4 years ago

Y and x have a proportional relationship, and y=12 when x=8. What is the value of x when y=18?

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Answer:

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4 years ago

Read 2 more answers

You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an

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Answer:

a

Yes

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d

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Step-by-step explanation:

From the question we are told that

Two fair dice, one green and one red were rolled

Generally the outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the probability of getting a 1 on a dice rolled is $P(1) = \frac{1}{6}$

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Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

$P(1 \& 5) = \frac{1}{6} *\frac{1}{6}$

$P(1 \& 5) = \frac{1}{36}$

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

$P(5 \& 1) = \frac{1}{6} *\frac{1}{6}$

$P(5 \& 1) = \frac{1}{36}$

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

$P(5 \& 1 | 1\& 5 ) = \frac{1}{36} + \frac{1}{36}$

$P(5 \& 1 | 1\& 5 ) = \frac{1}{18}$

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