Solve the equation for x, where x is restricted to the given interval. y= 8 cos 3x, for x in[0, pi/3] x = 1/3 y/8 x= 1/8 y/3 x= 5 y/3 x= 3 y/8 Use a calculator to give the value to the nearest degree. theta - sin^-1(0.8830) 57 degree 62 degree 60 degree 118 degree Write the product as a sum or different of trigonometric functions. 2 sin 2x sin 12 x cos 14x + cos 10x 1/2(cos 14x + cos 10x) sin 14x + sin 10x cos 10x - cos 14x Find the value of the real number y. y = cos^-1[squarerrot 2/2] pi/4 11 pi/6 7 pi/4 pi/6 Use Identities to find the exact value. cos 165 degree - squareroot 6 - squareroot 2/4 squareroot 2 - squareroot 6/4 squareroot 6 - squareroot 2/4 squareroot 6 + squareroot 2/4
The statement is false. The only shape with fo it lines of symmetry is a square
Answer:
a = 4/27 - b/54
Step-by-step explanation:
27a+1/2b=4
Subtract 1/2 b from each side
27a+1/2b - 1/2 b=4-1/2 b
27a = 4 - 1/2 b
Divide each side by 27
27a/27 = 4/27 - 1/2 b/27
a = 4/27 - b/54
