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krek1111 [17]
3 years ago
11

Is this statement true or false? A regular triangle has four lines of symmetry.

Mathematics
2 answers:
Fantom [35]3 years ago
8 0
The statement is false. The only shape with fo it lines of symmetry is a square
Alika [10]3 years ago
7 0

Answer:

The statement is false. The only shape with fo it lines of symmetry is a square

Step-by-step explanation:

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Twice a number plus 6 times the number is 72
ExtremeBDS [4]

Answer:

9

Step-by-step explanation:

Let the no be x

By the conditions given ,

2x + 6x = 72

8x = 72

x = 72/8

x = 9

therefore the no is 9

6 0
3 years ago
Read 2 more answers
Use the rules for multiplication by powers of 10 to calculate 3 times 100
Georgia [21]
3 * 100 = 300 because it is only asking you to claculate 3*100
3 0
3 years ago
Consider the graph of f(x) given below.
tiny-mole [99]

The functions could represent g(x) is B. g(x) = f(x - 5)

<h3>How can the function be determined?</h3>

Using the general equation g(x) =f(x)+ b

The g(x) has intercept of y=-2,

Then the  y-intercept of f(x) is at y=3

If we find the difference between both y-intercepts, we have

( -2 -3) = -5

Then b=-5

Hence, g(x) = f(x - 5) is correct.

Learn more about the  transformation at

brainly.com/question/4289712

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5 0
2 years ago
Simplify the following
Goshia [24]

Answer:

9

Step-by-step explanation:

Using the rules of logarithms

logx^{n} = nlogx

log_{b} b = 1

Then

log_{x} x^{9}

= 9log_{x} x

= 9

4 0
3 years ago
Find the third degree polynomial function that has an output of 40 when x=1, and has zeros −19 and −i?
Yanka [14]

Answer:

f(x) = (x + 19)(x^2 + 1)

Step-by-step explanation:

Complex numbers:

The following relation is important for complex numbers:

i^2 = -1

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Has zeros −19 and −i

If -i is a zero, its conjugate i is also a zero. So

f(x) = a(x - (-19))(x - (-i))(x - i) = a(x+19)(x+i)(x-i) = a(x+19)(x^2 - i^2) = a(x + 19)(x^2 + 1)

Output of 40 when x=1

This means that when x = 1, f(x) = 40. We use this to find the leading coefficient a. So

f(x) = a(x + 19)(x^2 + 1)

40 = a(20)(2)

40a = 40

a = 1

The polynomial is:

f(x) = (x + 19)(x^2 + 1)

3 0
3 years ago
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