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Advocard [28]
3 years ago
12

What is 1/6 plus 1/3 plus 1/2 equals to?

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
7 0
(In attachment) hope it helps:)

Scorpion4ik [409]3 years ago
4 0
1/6 + 1/3 + 1/2 is 1
first u need to find the GCF which is 6 here
convert all the denominators to 6
1/6 + 2/6 + 3/6
when you add them all together u get 6/6 which is also equivalent to 1
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What is the solution to the system of equations ? <br> Y=2/3 x + 3 <br> X= - 2
Firdavs [7]

Answer:

x = -2, y = 5/3

Step-by-step explanation:

we have the value of x already (-2).

x=-2

Plug it into the first equation y = 2/3x+3

y = 2/3(-2)+3

y = -4/3+3

y = -4/3+9/3

y = 5/3

x = -2, y = 5/3

7 0
3 years ago
Can anyone solve this x + 2 ( x + 2 + ( 2 x − 8 ) ) = x + 1 + ( 2 x − 5 ) x + 2 ( x + 2 + ( 2 x - 8 ) ) = x + 1 + ( 2 x - 5 )
r-ruslan [8.4K]

Answer:

simplify the equation to solve it, remove unnessecary parentheses and spaces.

5 0
3 years ago
According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe
Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 22% of couples meet online, hence p = 0.22.
  • A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

\mu = p = 0.22

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 0.25</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.25 - 0.22}{0.0338}

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

X = 0.2:

Z = \frac{X - \mu}{s}

Z = \frac{0.2 - 0.22}{0.0338}

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.22}{0.0338}

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

4 0
3 years ago
What is the equivalent of π/6 radians in degrees. Question and answers are in photo above
Karolina [17]

There are a number of radian-degree equivalents that it would be time-saving and otherwise worthwhile to memorize. π/6 = 30 degrees is one of these. For reference, here are a few others:

radians degrees

0 0

2π 360

π 180

π/2 90

π/4 45

and so on. Good luck!


3 0
4 years ago
Of the students at I.S. 59, 230 signed up for the school picnic. That was 50% of all students in the school. How many students a
Nastasia [14]

Answer: 460 students

Step-by-step explanation:

Based on the information given in the question, let the total number of students that attend I.S. 59 be represented by x.

Since we've been given the information that 230 signed up for the school picnic which was 50% of all students in the school. Then, the students in the school will be:

= 50% of x = 230

0.5 × x = 230

0.5x = 230

x = 230/0.5

x = 460

Therefore, 460 students attend the school.

4 0
3 years ago
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