The area of a sector is given by
.. A = (1/2)r^2*θ . . . . . θ is the central angle in radians
The area of an isosceles triangle with legs length r is
.. A = (1/2)r^2*sin(θ) . . . θ is the angle between same-length legs
The shaded area is the difference between these
.. A = (1/2)r^2*(θ -sin(θ))
.. = (1/2)*(18.6 m)^2*(π*123/180 -sin(123°))
.. ≈ 226.3 m^2
Answer:
5/6
Step-by-step explanation:
Well......I don't know how to tell you how to solve it....it just is .
The triangles ABD, ADC and ABC are similar (AA stands for "angle, angle" and means that the triangles have two of their angles equal).
If two triangles have two of their angles equal, the triangles are similar.
Therefore the sides of triangles are in proportion.
cross multiply
Use the Pythagorean theorem for calculate x:
-7+n=12
this leaves us with n=19
Answer:
V = (1/3)pi(r^2)h (the first one)
