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2 years ago

IXL math problem please help

Mathematics

1 answer:

Solnce55 [7]2 years ago

6 0

TX=10
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Can you explain to me how exponents work?

LuckyWell [14K]

Answer:

1^2 is one squared which means

1x1

1^3 is

1x1x1

2^4 is

2x2x2x2 which equals 16

Step-by-step explanation:

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3 years ago

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Uncle drew scored 28 points in 5 5/6 minutes. How many points did he average per minute

MA_775_DIABLO [31]

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Step-by-step explanation:

28/6

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3 years ago

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Find the equation of the circle with center (4,5) which passes through the y-intercept of the line 5x-2y+6=0

Elena-2011 [213]

Answer:

(x-4)^2 + (y-5)^2 = 20

Step-by-step explanation:

Rearrange the line equation of 5x - 2y + 6 = 0

So y = 5/2x +3

The y-intercept of the line equation is 3 as when x=0, y=3.

We know the Circle has the formula $(x-4)^2 + (y-5)^2 = ?^2$ from the question but with the intercept, we can find the entire equation as the y-intercept is (0,3) so we can substitute it into the equation to find the full equations so:

$(0-4)^2 + (3-5)^2 = ?^2$

This simplifies to:

$(-4)^2 +(-2)^2$ = $?^2$

16 + 4 = 20 = $?^2$

The answer is 20 so the equation of the circle is $(x-4)^2 + (y-5)^2 = 20$

3 0

2 years ago

A 20 foot extension ladder liens against a building if the base of the latter is placed 6 feet from the base of the building wha

goldenfox [79]

For this problem, you're going to need to use trig. More specifically, you need to use the tangent function:

tan (value) = opposite/adjacent

tan 75 = opposite/8 (Here, the opposite side is the length of the ladder)

8 * tan 75 = opposite

29.8564065 = opposite

So, the ladder is 29.9 feet.

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3 years ago

Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -

rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by D and its formula is

$D=b^2-4ac\\$

Where

a= the coefficient of the $x^{2}$

b= the coefficient of $x$

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .

Let us start with

$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

Hence we have two real roots for this equation.

$y = 2x^2 - 6x + 5\\$

$y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D$

Hence we do not have any real root for this quadratic

$y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\$

Hence D>0 and thus we have two real roots for this equation.

$y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\$

Hence we have one real root to this quadratic equation.

7 0

2 years ago