of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.
30 POINTS IF SOMEONE ANSWERS CORRECTLY (MATH)
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of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.
Step-by-step explanation:
X-2y=5 ; 2x-4y=10
• x - 2y = 5 • 2x -4y = 10
-2y = -x+5 -4y= -2x +10
y1 = ½x - 5/2 y2 = ½x -5/2
• => y1 = y2
½x -5/2 = ½x -5/2
the systems have no solution
• graph as attached
