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Archy [21]
2 years ago
13

Question 2. I have another question on my feed. Please help me solve!!!!

Mathematics
1 answer:
Maru [420]2 years ago
4 0

Answer:

A' (11, 4), B' (-10, -6), C' (7, -9)

Step-by-step explanation:

Since you are reflecting over the y-axis, you take the opposite of the x value. So if the x is positive, make it negative. If the x is negative, make it positive. The y coordinate stays the same.

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$7230 for 3.25% in 12 years
IceJOKER [234]

$2,819.70 is the answer

You multiply .0325×12×72.30

6 0
3 years ago
I need help with the top 3 plz
attashe74 [19]

Answer/Step-by-step explanation:

Recall: SOHCAHTOA

1. Reference angle = 70°

Adjacent side = x

Hypotenuse = 6 cm

Apply CAH. Thus,

Cos 70 = adj/hyp

Cos 70 = x/6

6 × cos 70 = x

2.05 = x

x = 2.05 cm

2. Reference angle = 45°

Adjacent side = x

Hypotenuse = 1.3 m

Applying CAH, we would have the following ratio:

Cos 45 = adj/hyp

Cos 45 = x/1.3

1.3 × cos 45 = x

0.92 = x

x = 0.92 m

3. The who diagram is not shown well. Some parts are missing, however you can still solve the problem just the same way we solved problem 1 and 2.

6 0
3 years ago
When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will
PtichkaEL [24]

Answer:

The correct answer is 9 m per second^{2}

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per second^{2}

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x  m per second^{2}.

∴ 54 = m × x

⇒ x = \frac{54}{6} = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per second^{2}.

6 0
3 years ago
Find the measure of BCD
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4 0
2 years ago
Add. (1+7x3−x2)+(x3+2+2x2) Express the answer in standard form. Enter your answer in the box.
Juli2301 [7.4K]
The answer to the question

6 0
3 years ago
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