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olganol [36]
3 years ago
11

What is the profit of $ 15

Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0

Answer:15$

Step-by-step explanation:

cuz its profit

lara31 [8.8K]3 years ago
3 0

Answer:

write full question plz

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2x - y - 4 = 0
Aleks [24]
So to start you should get x and y on the same side and get the numbers on one side. Then you should cancel out a variable. Because both y’s are 1 and they are opposite charges they will both cancel out to 0. Then add what is remaining which is the 2x and the 3x and equal that to +9-4 which equals 5. You want x to be all by itself so you would divide both sides by 5 and get that x=1. Then you would just substitue and solve for y. Hope this helped!
6 0
4 years ago
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Of the birds in Monica's pet shop, 1/5 are pigeons. Of the pigeons, 1/3 are white. Look at each expression. Can it be used to fi
KiRa [710]
1/15 of the birds are white
7 0
3 years ago
Which sequence of transformations performed on shape I confirms the congruence of shape II and shape I?
vampirchik [111]

Answer:

Option D. a 180° rotation about the origin and then a translation left 8 units.

Step-by-step explanation:

See the attached figure_1

From the graph: Point A'(-12,-6) is the image of point A(4,6)

We will check which sequence of transformations is true:

A. a reflection across the y-axis and then a translation down 16 units

A(4,6) ⇒(-4,6)⇒(-4,-10)   <u> (Wrong sequence)</u>

B. a 90° counterclockwise rotation about the origin and then a translation down 8 units

A(4,6) ⇒(-6,4)⇒(-6,-4)    <u>(Wrong sequence)</u>

C. a 90° clockwise rotation about the origin and then a translation left 16 units

A(4,6) ⇒(6,-4)⇒(-10,-4)    <u>(Wrong sequence)</u>

D. a 180° rotation about the origin and then a translation left 8 units

A(4,6) ⇒(-4,-6)⇒(-12,-6)A'   <u>(True sequence)</u>

<u></u>

Note: the rules is the attached figure_2

4 0
3 years ago
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Which of the following sets of number does square of 121 NOT belong
madreJ [45]

Answer:

D

Step-by-step explanation:

Squaring 121 will still be a real number, a rational number, and an integer. Therefore, it is not an irrational number.

8 0
3 years ago
Encuentra en cada producto notable el error o errores,enciérralo y escribe el resultado correcto.
lbvjy [14]

Given:

The equation is:

(2x+3y)(2x-3y)=4x^2+6y^2

To find:

The error in the given equation and correct it.

Solution:

We have,

(2x+3y)(2x-3y)=4x^2+6y^2

Taking left-hand side, we get

L.H.S.=(2x+3y)(2x-3y)

L.H.S.=(2x)^2-(3y)^2                 [\because a^2-b^2=(a-b)(a+b)]

L.H.S.=(2)^2(x)^2-(3)^2(y)^2       [\because (ab)^x=a^xb^x]

L.H.S.=4x^2-9y^2

It is not equal to right-hand side 4x^2+6y^2. In the right hand side, there must be a negative sign instead of positive sign.

Therefore, (2x+3y)(2x-3y)=4x^2-6y^2.

8 0
3 years ago
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